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\(\dfrac{5}{9}+\dfrac{7}{12}-\dfrac{3}{4}=\dfrac{5.4}{36}+\dfrac{7.3}{36}-\dfrac{3.9}{36}\\ =\dfrac{20+21-27}{36}\\ =\dfrac{14}{36}=\dfrac{7}{18}\)
a) ta cs: 3645 - 3644 = 3644.(36-1) =3644.35
3644 - 3643 = 3643.35
=> 3645 - 3644 > 3644 - 3643
b) ta cs: 3450 = (33)150 = 27150
5300 = (52)150 = 25150
=> 3450 > 5300
c) ta cs: 3452 = 345.345 = 345.(342+ 3) = 345.342 + 345.3
342 . 348 = 342.(345+3) = 342.345 + 342.3
=> 3452 > 342.348
d) ta cs: (1+2+3+4)2 = 102 =100
13 + 23 + 33 + 43 = 100
=>...
Cách 1
\(2\dfrac{3}{4}\)+ \(5\dfrac{7}{9}\)= \(\dfrac{11}{4}+\dfrac{47}{9}\)
= \(\dfrac{99}{36}+\dfrac{188}{36}\)
= \(\dfrac{287}{36}\)= 7,9722...
Cách 2
\(2\dfrac{3}{4}+5\dfrac{7}{8}=2\dfrac{55}{36}+5\dfrac{55}{36}\)
= \(7\dfrac{55}{36}=8\dfrac{19}{36}\)
Cách 1 mình làm nhầm bài đúng phải là
\(2\dfrac{3}{4}+5\dfrac{7}{9}=\dfrac{11}{4}+\dfrac{52}{9}=\dfrac{99}{36}+\dfrac{208}{36}\)
=\(\dfrac{307}{36}\)=8,527777778
\(E=\left(\frac{-2}{3}.\frac{-9}{10}\right).\left(\frac{-5}{6}.\frac{-14}{15}\right).\left(\frac{-20}{21}.\frac{-27}{28}\right).\frac{-35}{36}\)
\(E=\frac{3}{5}.\frac{7}{9}.\frac{45}{49}.\frac{-35}{36}\)
\(E=\left(\frac{3}{5}.\frac{-35}{36}\right).\left(\frac{7}{9}.\frac{45}{49}\right)\)
\(E=\frac{-7}{12}.\frac{5}{7}\)
\(E=\frac{-5}{12}\)
vậy \(E=\frac{-5}{12}\)
E=-2/3.-5/6.-9/10.-14/15.-20/21.-27/28.-35/36
=-2/3.-5/2.3.-3.3/2.5.-2.7/3.5.-4.5/3.7.3.3.3/4.7.-5.7/4.3.3
=-5/12
\(a,\)\(\frac{1}{2}.\left(\frac{2}{9}+\frac{3}{7}-\frac{5}{37}\right)\)
\(\Rightarrow\frac{1}{2}.\left(\frac{2.259}{2331}+\frac{3.333}{2331}-\frac{5.63}{2331}\right)\)
\(\Rightarrow\frac{1}{2}.\left(\frac{518}{2331}+\frac{999}{2331}-\frac{315}{2331}\right)\)
\(\Rightarrow\frac{1}{2}.\left(\frac{518+999-315}{2331}\right)\)
\(\Rightarrow\frac{1}{2}.\frac{1202}{2331}\)
\(\Rightarrow\frac{601}{2331}\)
\(b,\)\(\left(-\frac{5}{28}+1,75+\frac{8}{35}\right):\left(-3\frac{9}{20}\right)\)
\(\Rightarrow\frac{9}{5}:\left(-\frac{69}{20}\right)\)
\(=-\frac{12}{23}\)
\(c,\)\(\frac{1}{3}.\frac{1}{5}-\frac{7}{27}.\frac{36}{14}\)
\(=\frac{1}{15}-\frac{2}{3}\)
\(=\frac{1}{15}-\frac{10}{15}=-\frac{9}{15}=-\frac{3}{5}\)
\(d,\)\(70,5-528:\frac{15}{2}\)
\(=70,5-\frac{352}{5}\)
\(=\frac{1}{10}\)
\(a,\frac{3}{27}+\frac{1}{4}-\frac{1}{9}=\frac{3}{27}+\frac{1}{4}-\frac{3}{27}=\frac{3}{27}-\frac{3}{27}+\frac{1}{4}=\frac{1}{4}\)
\(b,\frac{72}{25}\cdot\frac{75}{36}=\frac{72\cdot75}{25\cdot36}=\frac{2\cdot36\cdot25\cdot3}{25\cdot36}=\frac{2\cdot3}{1\cdot1}=6\)
\(c,\frac{36}{49}:\frac{48}{14}=\frac{36}{49}\cdot\frac{14}{48}=\frac{36\cdot14}{49\cdot48}=\frac{3\cdot12\cdot2\cdot7}{7\cdot7\cdot4\cdot12}=\frac{3\cdot2}{7\cdot4}=\frac{6}{28}=\frac{3}{14}\)
\(d,\frac{39}{23}:26=\frac{39}{23}\cdot\frac{1}{26}=\frac{39}{23\cdot26}=\frac{3\cdot13}{23\cdot2\cdot13}=\frac{3}{23\cdot2}=\frac{3}{46}\)
\(e,45:\frac{15}{2}=\frac{45}{1}\cdot\frac{2}{15}=\frac{45\cdot2}{15}=\frac{3\cdot15\cdot2}{15}=\frac{6}{1}=6\)
\(g,\frac{57}{8}:\frac{3}{4}-\frac{15}{7}\cdot\frac{14}{25}=\frac{57\cdot4}{8\cdot3}-\frac{15\cdot14}{7\cdot25}=\frac{3\cdot19\cdot4}{2\cdot4\cdot3}-\frac{3\cdot5\cdot2\cdot7}{7\cdot5\cdot5}\)
\(=\frac{19}{2}-\frac{3\cdot2}{5}=\frac{95}{10}-\frac{12}{10}=\frac{83}{10}\)
{143-[(36:4+14]}.27:36+174
{143-[(9+14)]}.27:36+174
{143-23}.27:36+174
120.27:36+174
3240:36+174
90+174
264
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