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C1:
(1/4+1/7)x1/3=11/28x1/3
=11/84
C2:
(1/4=1/7)x1/3=1/3x1/4+1/3x1/7
=1/12+1/21
=11/84
cho mk nhé, có fb kb vs mk đi nè <3 <3
\(\left(\dfrac{1}{4}+\dfrac{1}{7}\right)\times\dfrac{1}{3}\\ =\left(\dfrac{7}{28}+\dfrac{4}{28}\right)\times\dfrac{1}{3}\\ =\dfrac{11}{28}\times\dfrac{1}{3}\\ =\dfrac{11}{84}\)
a: =8/15x1/4=2/15
b: \(=\dfrac{5}{3}\cdot\dfrac{4}{5}\cdot\dfrac{6}{7}=\dfrac{24}{21}=\dfrac{8}{7}\)
c: \(=\dfrac{2}{5}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)=\dfrac{2}{5}\)
a) \(\left(\frac{1}{5}+\frac{3}{5}\right)\times\frac{1}{4}\)
\(=\frac{4}{5}\times\frac{1}{4}\)
\(=\frac{4}{20}=\frac{1}{5}\)
\(\left(\frac{1}{5}+\frac{3}{5}\right)\times\frac{1}{4}=\frac{1}{5}\times\frac{1}{4}+\frac{3}{5}\times\frac{1}{4}\)
\(=\frac{1}{20}+\frac{3}{20}\)
\(=\frac{4}{20}=\frac{1}{5}\)
b) \(\left(\frac{7}{9}-\frac{2}{9}\right)\times\frac{3}{2}\)
\(=\frac{5}{9}\times\frac{3}{2}\)
\(=\frac{15}{18}=\frac{5}{6}\)
\(\left(\frac{7}{9}-\frac{2}{9}\right)\times\frac{3}{2}=\frac{7}{9}\times\frac{3}{2}-\frac{2}{9}\times\frac{3}{2}\)
\(=\frac{21}{18}-\frac{6}{18}\)
\(=\frac{15}{18}=\frac{5}{6}\)
c) \(\left(\frac{11}{13}-\frac{9}{13}\right)\times\frac{39}{21}\)
\(=\frac{2}{13}\times\frac{39}{21}\)
\(=\frac{78}{273}=\frac{2}{7}\)
\(\left(\frac{11}{13}-\frac{9}{13}\right)\times\frac{39}{21}=\frac{11}{13}\times\frac{39}{21}-\frac{9}{13}\times\frac{39}{21}\)
\(=\frac{429}{273}-\frac{351}{273}\)
\(=\frac{78}{273}=\frac{2}{7}\)
a,\(\left(\frac{1}{5}+\frac{3}{5}\right)x\frac{1}{4}\)
=\(\frac{4}{5}x\frac{1}{4}\)
=\(\frac{4}{20}\)
=\(\frac{1}{5}\)
,\(\left(\frac{1}{5}+\frac{3}{5}\right)x\frac{1}{4}\)
=\(\frac{4}{5}x\frac{1}{4}\)
=\(\frac{4x1}{5x4}\)
=\(\frac{1x1}{5x1}\)
=\(\frac{1}{5}\)
Cách 1 : \(\left(\frac{1}{4}-\frac{1}{7}\right)\times\frac{1}{3}\)
\(=\frac{3}{28}\times\frac{1}{3}\)
\(=\frac{1}{28}\)
Cách 2:\(\left(\frac{1}{4}-\frac{1}{7}\right)\times\frac{1}{3}\)
\(=\frac{1}{4}\times\frac{1}{3}-\frac{1}{7}\times\frac{1}{3}\)
\(=\frac{1}{12}-\frac{1}{21}\)
\(=\frac{1}{28}\)
a: \(=\dfrac{2}{3}\cdot\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{2}{3}\cdot\dfrac{2}{3}=\dfrac{4}{9}\)
b: \(=\dfrac{5}{6}\cdot\dfrac{1}{5}=\dfrac{1}{6}\)
a. C1: \(\dfrac{8}{15}.\dfrac{5}{6}=\dfrac{4}{9}\)
C2: \(\dfrac{2}{3}.\dfrac{4}{5}.\dfrac{5}{6}=\dfrac{2.4.5}{3.5.3.2}\)
Triệt tiêu phần giống nhau ở tử và mẫu ta có
\(=\dfrac{4}{9}\)
b. \(C1:\left(\dfrac{1}{2}+\dfrac{1}{3}\right).\dfrac{1}{5}=\dfrac{5}{6}.\dfrac{1}{5}=\dfrac{1}{6}\)
C2: \(\dfrac{1}{2}.\dfrac{1}{5}+\dfrac{1}{3}.\dfrac{1}{5}=\dfrac{1}{10}+\dfrac{1}{15}=\dfrac{1}{6}\)
C1 : 11/28 x 1/3 =11/84
C2 : 1/4 x1/3 + 1/7 x 1/3 = 11/84
C1 : 3/28 x 1/3 =1/28
C2 1/4 x1/3 - 1/7 x 1/3 =1/28