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1. 2x=16\(\Rightarrow\)X=4
2. 22x-1=27
\(\Rightarrow\)27=22.4-1
Vậy x =4

a) \(4^n=4096\Rightarrow4^n=4^6\Rightarrow n=6\)
b) \(5^n=15625\Rightarrow5^n=5^6\Rightarrow n=6\)
c) \(6^{n+3}=216\Rightarrow6^{n+3}=6^3\Rightarrow n+3=3\Rightarrow n=0\)
d) \(x^2=x^3\Rightarrow x^3-x^2=0\Rightarrow x^2\left(x-1\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x-1=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
e) \(3^{x-1}=27\Rightarrow3^{x-1}=3^3\Rightarrow x-1=3\Rightarrow x=4\)
f) \(3^{x+1}=9\Rightarrow3^{x+1}=3^2\Rightarrow x+1=2\Rightarrow x=1\)
g) \(6^{x+1}=36\Rightarrow6^{x+1}=6^2\Rightarrow x+1=2\Rightarrow x=1\)
h) \(3^{2x+1}=27\Rightarrow3^{2x+1}=3^3\Rightarrow2x+1=3\Rightarrow2x=2\Rightarrow x=1\)
i) \(x^{50}=x\Rightarrow x^{50}-x=0\Rightarrow x\left(x^{49}-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x^{49}-1=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x^{49}=1=1^{49}\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)
4n = 4096
4n = 212
n = 12
5n = 15625
5n = 56
n = 6
6n+3 = 216
6n+3 = 23.33
6n+3 = 63
n + 3 = 3

Bài 9,
62x73+36x33=36x73+36x27=36(73+27)=36x100=3600.
197-\([\)6x(5-1)2+20220\(]\):5=197-\([\)6x16+1\(]\):5=197-97:5=197-97/5=888/5.
Bài 10,
21-4x=13
=>4x=21-13=8
=>x=8:4=2.
30:(x-3)+1=45:43=42=16
=>30:(x-3)=16-1=15
=>x-3=30:15=2
=>x=2+3=5.
(x-1)3+5x6=38
=>(x-1)3+30=38
=>(x-1)3=38-30=8=23
=>x-1=2
=>x=3.

a) \(\left(x-\frac{2}{3}\right)^2=\frac{25}{36}\)
\(\Rightarrow x-\frac{2}{3}=\pm\frac{5}{6}\)
Nếu \(x-\frac{2}{3}=\frac{5}{6}\Rightarrow x=\frac{5}{6}+\frac{2}{3}=\frac{3}{2}\)
Nếu \(x-\frac{2}{3}=\frac{-5}{6}\Rightarrow x=\frac{-5}{6}+\frac{2}{3}=\frac{-1}{6}\)
Vậy \(x=\left\{-\frac{1}{6};\frac{3}{2}\right\}\)
b) \(\left(\frac{3}{4}-x\right)^3=-8\)
Mà \(\left(-2\right)^2=-8\)
\(\Rightarrow\frac{3}{4}-x=-2\Rightarrow x=\frac{3}{4}-\left(-2\right)=\frac{3}{4}+2=\frac{11}{4}\)
Vậy \(x=\left\{\frac{11}{4}\right\}\)

1) 62 . x = 36
=> x = 36 / 36 = 1
2) 9x - 42 = 11
9x - 16 = 11
9x = 11 + 16 =27
=> x = 27/9=3
3) 10 + 2x = 42
2x = 16 - 10 =6
=> x = 3
4) 231 - ( x - 6 ) =103
( x - 6 ) = 231-103=128
=> x = 128+6=134
5) 10 + 3x = 45 / 42
3x = 43-10=64-10=54
x = 18
6)25 + 52x = 82 + 62
25 + 25x = 100
25x = 100-25=75
=> x = 75/25=3
*Chúc bạn học tốt*
1) 62.x=36 2) 9.x-42=11 3)10+2.x=42 4)231-(x-6)=103 5)10+3x=45:42 6)25+52.x=82+62
36.x=36 9.x-16=11 10+2.x=16 x-6 = 231-103 10+3x=43 25+25.x =64+36
x=36:36 9.x =11+16 2.x =16-10 x-6 =128 10+3x=64 25+25.x =100
x=1 9.x =27 2.x =6 x =128+6 3x=64-10 25.x =100-25
x =27:9 x =6:2 x =134 3x=54 25.x =75
x =3 x =3 x=54:3 x =75:25
x=18 x =3
\(\left(\frac{1}{3}x+\frac{1}{4}\right)^2=\frac{1}{36}\)
=> \(\left(\frac{1}{3}x+\frac{1}{4}\right)^2=\left(\frac{1}{6}\right)^2\)
=> \(\orbr{\begin{cases}\frac{1}{3}x+\frac{1}{4}=\frac{1}{6}\\\frac{1}{3}x+\frac{1}{4}=-\frac{1}{6}\end{cases}}\)
=> \(\orbr{\begin{cases}\frac{1}{3}x=-\frac{1}{12}\\\frac{1}{3}x=-\frac{5}{12}\end{cases}}\)
=> \(\orbr{\begin{cases}x=-\frac{1}{4}\\x=-\frac{5}{4}\end{cases}}\)
Vậy ...
Trả lời..............
X có 2 giá trị:
X=-1/4 và X=-5/4
.................học tốt..................
Tớ không biết đúng hay sai đâu nha