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Câu 1 sai đề.
Câu 2:
\(23-\frac{x}{25}=\frac{4}{5}\)
\(\frac{x}{25}=\frac{111}{5}\)
\(x=555\)
Câu 2:
23−x25=4523−x25=45
x25=1115x25=1115
x=555
b) \(23-\frac{x}{25}=\frac{4}{5}\)
\(\frac{x}{25}=23-\frac{4}{5}\)
\(\frac{x}{25}=\frac{111}{5}=\frac{555}{25}\)
=> x = 555
`(13+x)/20 = 3/4`
`(13+x) xx4=3xx20`
`(13+x)xx4=60`
`13+x=60:4`
`13+x=15`
`x=15-13`
`x=2`
__
`(23-x)/25 =4/5`
`(23-x)xx5=4xx25`
`(23-x)xx5=100`
`23-x=100:5`
`23-x=20`
`x=23-20`
`x=3`
Bài 2:
a, \(\dfrac{5}{23}\) \(\times\) \(\dfrac{17}{26}\) + \(\dfrac{5}{23}\) \(\times\) \(\dfrac{9}{26}\)
= \(\dfrac{5}{23}\) \(\times\) ( \(\dfrac{17}{26}\) + \(\dfrac{9}{26}\))
= \(\dfrac{5}{23}\) \(\times\) \(\dfrac{26}{26}\)
= \(\dfrac{5}{23}\)
b, \(\dfrac{3}{4}\) \(\times\) \(\dfrac{7}{9}\) + \(\dfrac{7}{4}\) \(\times\) \(\dfrac{3}{9}\)
= \(\dfrac{7}{12}\) + \(\dfrac{7}{12}\)
= \(\dfrac{14}{12}\)
= \(\dfrac{7}{6}\)
Bài 1:
a; (\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\)) x \(\dfrac{3}{4}\) = \(\dfrac{1}{4}\)
\(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) : \(\dfrac{3}{4}\)
\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) x \(\dfrac{4}{3}\)
\(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{3}\)
\(\dfrac{1}{4}x\) = \(\dfrac{1}{3}\) + \(\dfrac{1}{8}\)
\(\dfrac{1}{4}\) \(x\)= \(\dfrac{8}{24}\) + \(\dfrac{11}{24}\)
\(\dfrac{1}{4}x=\dfrac{11}{24}\)
\(x=\dfrac{11}{24}:\dfrac{1}{4}\)
\(x=\dfrac{11}{24}\times4\)
\(x=\dfrac{11}{6}\)
b; \(\dfrac{12}{5}:x\) = \(\dfrac{14}{3}\) x \(\dfrac{4}{7}\)
\(\dfrac{12}{5}\) : \(x\) = \(\dfrac{8}{3}\)
\(x\) = \(\dfrac{12}{5}\) : \(\dfrac{8}{3}\)
\(x\) = \(\dfrac{12}{5}\) x \(\dfrac{3}{8}\)
\(x\) = \(\dfrac{9}{10}\)
(273+485)*16-483:3*4
=758*16-483:3*4
=12128-161*4
=12128-644
=11484
nhớ cick cho mk nhé bạn!
\(\frac{13+x}{20}=\frac{3}{4}\)
\(\Rightarrow\left(13+x\right).4=3.20\)
\(\Rightarrow\left(13+x\right).4=60\)
=> 13 + x = 60 : 4
=> 13 + x = 5
=> x = 5 - 13
=> x = -8
\(\frac{22-x}{25}=\frac{4}{5}\)
=> (22 - x) . 5 = 4 . 25
=> (22 - x) .5 = 100
=> 22 - x = 100 : 5
=> 22 - x = 20
=> x = 22 - 20
=> x = 2