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\(\left(\frac{3}{9}.x-5\right)^2=\frac{9}{49}\)
\(\Rightarrow\orbr{\begin{cases}\frac{3}{9}x-5=\frac{3}{7}\\\frac{3}{9}x-5=-\frac{3}{7}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}\frac{3}{9}x=\frac{3}{7}+5\\\frac{3}{9}x=-\frac{3}{7}+5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}\frac{3}{9}x=\frac{38}{7}\\\frac{3}{9}x=\frac{32}{7}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{114}{7}\\x=\frac{96}{7}\end{cases}}\)
Vậy \(\orbr{\begin{cases}x=\frac{114}{7}\\x=\frac{96}{7}\end{cases}}\)
Chúc bạn học tốt !!!!
a: \(\Leftrightarrow3x+9=-2x+6\)
=>5x=-3
hay x=-3/5
b: =>3/x=y/35=3/7
=>x=7; y=15
c: =>9x/5=-3/5
=>9x=-3
hay x=-1/3
d: =>x+2/26=-1/4
=>x+2=-13/2
hay x=-17/2
2840 + [ ( 999 - 9 x X ) : 60 ] x 24 = 3200
=> [ ( 999 - 9 x X ) : 60 ] x 24 = 3200 - 2840 = 360
=> ( 999 - 9 x X ) : 60 = 360 : 24 = 15
= > 999 - 9 x X = 15 x 60 = 900
= > 9 x X = 999 - 900 = 99
=> X = 99 : 9 = 11
Đúng NHa !!!
2840+[(999-9.x):60].24=3200
[(999-9.x):60].24 = 3200 - 2840
[(999-9.x):60].24 = 360
(999-9.x):60 = 360 : 24
(999-9.x):60 = 15
999-9.x = 15 . 60
999-9.x = 900
9.x = 999 - 900
9.x = 99
x = 99 : 9
x = 11
Vậy x=1
\(\left(\dfrac{5}{7}-\dfrac{7}{7}\right)-\left[0,2-\left(-\dfrac{2}{7}-\dfrac{1}{10}\right)\right]\)
=\(-\dfrac{2}{7}-\left[\dfrac{1}{5}+\dfrac{2}{7}+\dfrac{1}{10}\right]\)
=\(-\dfrac{2}{7}-\dfrac{1}{5}-\dfrac{2}{7}-\dfrac{1}{10}\)
=\(\left(-\dfrac{2}{7}-\dfrac{2}{7}\right)-\left(\dfrac{1}{5}+\dfrac{1}{10}\right)\)
=\(-\dfrac{4}{7}-\left(\dfrac{2}{10}+\dfrac{1}{10}\right)\)
=\(-\dfrac{4}{7}-\dfrac{3}{10}\)
=\(-\dfrac{40}{70}-\dfrac{21}{70}\)
=\(-\dfrac{61}{70}\)
(3 - \(\dfrac{1}{4}\) + \(\dfrac{2}{3}\)) - (5 - \(\dfrac{1}{3}\) - \(\dfrac{5}{6}\)) - (6 - \(\dfrac{7}{4}\) - \(\dfrac{3}{2}\))
= 3 - \(\dfrac{1}{4}\) + \(\dfrac{2}{3}\) - 5 + \(\dfrac{1}{3}\) + \(\dfrac{5}{6}\) - 6 + \(\dfrac{7}{4}\) + \(\dfrac{3}{2}\)
= (3 - 5 - 6) + ( \(\dfrac{7}{4}\) - \(\dfrac{1}{4}\)) + (\(\dfrac{2}{3}\) + \(\dfrac{1}{3}\)) + \(\dfrac{3}{2}\) + \(\dfrac{5}{6}\)
= - 8 + \(\dfrac{3}{2}\) + 1 + \(\dfrac{3}{2}\) + \(\dfrac{5}{6}\)
= (- 8 + 1) + (\(\dfrac{3}{2}\) + \(\dfrac{3}{2}\)) + \(\dfrac{5}{6}\)
= -7 + 3 + \(\dfrac{5}{6}\)
= - 4 + \(\dfrac{5}{6}\)
= \(\dfrac{-19}{6}\)
\(\left(x+\frac{5}{3}\right)\left(x-\frac{5}{4}\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}\left(x+\frac{5}{3}\right)=0\\\left(x-\frac{5}{4}\right)=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-\frac{5}{3}\\x=\frac{5}{4}\end{cases}}}\)
\(\frac{1}{3}+\frac{1}{2}\div x=-4\)
\(\frac{1}{2}\div x=-4-\frac{1}{3}\)
\(\frac{1}{2}\div x=-\frac{13}{3}\)
\(x=-\frac{3}{26}\)
`1/3 - 4/9 xx x =3/5`
`=> 4/9 xx x =1/3-3/5`
`=> 4/9 xx x = 5/15 -9/15`
`=> 4/9 xx x = -4/15`
`=>x= -4/15 : 4/9`
`=>x=-4/15 xx 9/4`
`=>x=-3/5`