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a: x^3-2x-4=0
=>x^3-2x^2+2x^2-4x+2x-4=0
=>(x-2)(x^2+2x+2)=0
=>x-2=0
=>x=2
b: 2x^3-12x^2+17x-2=0
=>2x^3-4x^2-8x^2+16x+x-2=0
=>(x-2)(2x^2-4x+1)=0
=>x=2; \(x=\dfrac{4\pm\sqrt{14}}{2}\)
|2x - 1| + (y - 2)² ≤ 0 (1)
Do |2x - 1| ≥ 0 và (y - 2)²⁰²² ≥ 0 (với mọi x, y ∈ R)
(1) ⇒ |2x - 1| + (y - 2)²⁰²² = 0
⇒ |2x - 1| = 0 và (y - 2)²⁰²² = 0
*) |2x - 1| = 0
2x - 1 = 0
2x = 1
x = 1/2
*) (y - 2)²⁰²² = 0
y - 2 = 0
y = 2
⇒ B = 12x² + 4xy²
= 12.(1/2)² + 4.(1/2).2²
= 3 + 8
= 11
\(\left(2x-5\right).3+1=-26\)
=> (2x - 5).3 = -27
=> 2x - 5 = -9
=> 2x = -4
=> x = -2
\(\frac{x}{3}=\frac{y}{7}\Rightarrow\frac{2x}{6}=\frac{y}{7}\)
áp dụng tính chất của dãy tỉ số bằng nhau ta có
\(\frac{2x}{6}=\frac{y}{7}=\frac{2x+y}{6+7}=\frac{26}{13}=2\)
\(\frac{x}{3}=2\Rightarrow x=3.2=6\)
\(\frac{y}{7}=2\Rightarrow y=7.2=14\)
ta có:x/3=y/7
suy ra x=3y/7 (1)
thay (1) vào 2x+y=26 ta được:
2.3y/7+y=26
6y/7+y=26
13/7.y=26
y=14 nên x =6
a) 2x(x - 5) - x(2x + 3) = 26
⇒ 2x² - 10x - 2x² - 3x = 26
⇒ -13x = 26
⇒ x = -2
chúc bạn học tốt
\(a,-\dfrac{x}{2}+\dfrac{2x}{3}+\dfrac{x+1}{4}+\dfrac{2x+1}{6}=\dfrac{8}{3}\)
\(\Rightarrow-\dfrac{6x}{12}+\dfrac{8x}{12}+\dfrac{3\left(x+1\right)}{12}+\dfrac{2\left(2x+1\right)}{12}=\dfrac{8}{3}\)
\(\Rightarrow\dfrac{-6x+8x+3x+3+4x+2}{12}=\dfrac{8}{3}\)
\(\Rightarrow\dfrac{9x+5}{12}=\dfrac{8}{3}\)
\(\Rightarrow27x+15=96\)
\(\Rightarrow27x=81\)
\(\Rightarrow x=3\left(tm\right)\)
\(b,\dfrac{3}{2x+1}+\dfrac{10}{4x+2}-\dfrac{6}{6x+3}=\dfrac{12}{26}\)
\(\Rightarrow\dfrac{3}{2x+1}+\dfrac{10}{2\left(2x+1\right)}-\dfrac{6}{3\left(2x+1\right)}=\dfrac{6}{13}\)
\(\Rightarrow\dfrac{3}{2x+1}+\dfrac{5}{2x+1}-\dfrac{2}{2x+1}=\dfrac{6}{13}\)
\(\Rightarrow\dfrac{3+5-2}{2x+1}=\dfrac{6}{13}\)
\(\Rightarrow\dfrac{6}{2x+1}=\dfrac{6}{13}\)
\(\Rightarrow2x+1=13\)
\(\Rightarrow2x=12\)
\(\Rightarrow x=6\left(tm\right)\)
#Toru
a) \(-\dfrac{x}{2}+\dfrac{2x}{3}+\dfrac{x+1}{4}+\dfrac{2x+2}{6}=\dfrac{8}{3}\)
\(\Rightarrow\dfrac{-6x}{12}+\dfrac{8x}{12}+\dfrac{3\left(x+1\right)}{12}+\dfrac{2\left(2x+1\right)}{12}=\dfrac{4\cdot8}{12}\)
\(\Rightarrow-6x+8x+3x+3+4x+2=32\)
\(\Rightarrow9x+5=32\)
\(\Rightarrow9x=32-5\)
\(\Rightarrow9x=27\)
\(\Rightarrow x=\dfrac{27}{9}\)
\(\Rightarrow x=3\)
b) \(\dfrac{3}{2x+1}+\dfrac{10}{4x+2}-\dfrac{6}{6x+3}=\dfrac{12}{26}\) (ĐK: \(x\ne-\dfrac{1}{2}\))
\(\Rightarrow\dfrac{3}{2x+1}+\dfrac{10}{2\left(2x+1\right)}-\dfrac{6}{3\left(2x+1\right)}=\dfrac{6}{13}\)
\(\Rightarrow\dfrac{3}{2x+1}+\dfrac{5}{2x+1}-\dfrac{2}{2x+1}=\dfrac{6}{13}\)
\(\Rightarrow\dfrac{6}{2x+1}=\dfrac{6}{13}\)
\(\Rightarrow2x+1=13\)
\(\Rightarrow2x=12\)
\(\Rightarrow x=\dfrac{12}{2}\)
\(\Rightarrow x=6\left(tm\right)\)
\(13\frac{1}{3}:1\frac{1}{3}=26:\left(2x-1\right)\)
\(\Rightarrow\frac{40}{3}:\frac{4}{3}=26:\left(2x-1\right)\)
\(\Rightarrow10=26:\left(2x-1\right)\)
\(\Rightarrow26:\left(2x-1\right)=10\)
\(\Rightarrow2x-1=26:10\)
\(\Rightarrow2x-1=\frac{13}{5}\)
\(\Rightarrow2x=\frac{13}{5}+1\)
\(\Rightarrow2x=\frac{18}{5}\)
\(\Rightarrow x=\frac{18}{5}:2\)
\(\Rightarrow x=\frac{9}{5}\)
\(\frac{x}{2}=\frac{y}{5}=\frac{z}{3}va2x+3y-2z=-26\)
\(\frac{2x}{4}=\frac{3y}{15}=\frac{2z}{6}\)
ap dung tinh chat day ti so bang nhau ta co
\(\frac{2x}{4}=\frac{3y}{15}=\frac{2z}{6}=\frac{2x+3y-2z}{4+15-6}=\frac{-26}{13}=-2\)
suy ra x=-4 ; y=-10 ; z=-6
Ta có: \(\frac{x}{2}=\frac{y}{5}=\frac{z}{3}.\)
=> \(\frac{2x}{4}=\frac{3y}{15}=\frac{2z}{6}\) và \(2x+3y-2z=-26.\)
Áp dụng tính chất dãy tỉ số bằng nhau ta được:
\(\frac{2x}{4}=\frac{3y}{15}=\frac{2z}{6}=\frac{2x+3y-2z}{4+15-6}=\frac{-26}{13}=-2.\)
\(\left\{{}\begin{matrix}\frac{x}{2}=-2=>x=\left(-2\right).2=-4\\\frac{y}{5}=-2=>y=\left(-2\right).5=-10\\\frac{z}{3}=-2=>z=\left(-2\right).3=-6\end{matrix}\right.\)
Vậy \(\left(x;y;z\right)=\left(-4;-10;-6\right).\)
Chúc bạn học tốt!
bằng 49/24
đáp án là 49/24. Hok tốt