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(12x-5).(4x-1)-(3x-7).16x=81
48x²-12x-20x+5-(48x²-112x)=81
48x²-12x-20x+5-48x²+112x=81
(48x²-48x²)+(112x-12x-20x)+5=81
0+100x-20x+5=81
80x+5=81
80x=81-5
80x=76
x=76:80
x=19/20
Vậy x=19/20
Hok tốt
(12x - 5)(4x - 1) + (3x - 7)(1 - 16x) = 81
48x2 - 32x + 5 - 48x + 115x - 7 = 81
83x - 2 = 81
83x = 83
=> x = 1
(12x-5).(4x-1)+(3x-7).(1-16x) = 81
=> 48x2-12x-20x+5+3x-48x2-7+112x = 81
=> 83x-2 = 81
=> 83x = 81+2
=> 83x = 83
=> x = 83:83
=> x = 1
( 12x - 5 ) ( 4x -1 ) + ( 3x - 7 ) ( 1 - 16x ) = 81
48x2 - 12x - 20x + 5 + 3x - 48x2 - 7 + 112x = 81
83x = 81 - 5 + 7
83x = 83
x = 83/83
x = 1
Chúc bn hok tốt nha
\(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)
\(\text{⇔}48x^2-32x+5-48x^2-7+115x=81\)
\(\text{⇔}83x-2=81\)
\(\text{⇔}83x=83\)
\(\text{⇔}x=1\)
Vậy: x=1
Ta có: \(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)
\(\Leftrightarrow48x^2-12x-20x+5+3x-48x^2-7+112x=81\)
\(\Leftrightarrow83x=83\)
hay x=1
\(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)
\(\Leftrightarrow48x^2-32x+5+48x^2+115x-7=81\)
\(\Leftrightarrow83x=83\)
\(\Leftrightarrow x=1\)
\(\Leftrightarrow48x^2-12x-20x+5+3x-48x^2-7+112x=81\\ \Leftrightarrow83x=83\Leftrightarrow x=1\)
Rút gọn vế trái:
VT = (12x – 5)(4x – 1) + (3x – 7)(1 – 16x)
= 12x.(4x – 1) + (–5).(4x – 1) + 3x.(1 – 16x) + (–7).(1 – 16x)
= 12x.4x+ 12x.(–1) + (–5).4x + (–5).(–1) + 3x.1 + 3x.(–16x) + (–7).1 + (–7).(–16x)
= 48x2 – 12x – 20x + 5 + 3x – 48x2 – 7 + 112x
= (48x2 – 48x2) + (– 12x – 20x + 3x + 112x) + (5 – 7)
= 83x – 2
Vậy ta có:
83x – 2 = 81
83x = 81 + 2
83x = 83
x = 83 : 83
x = 1.
(12x - 5)(4x - 1) + (3x - 7)(1 -16x) = 81
48x2 – 12x – 20x + 5 + 3x - 48x2 – 7 + 112x = 81
83x – 2 = 81
83x = 83
x = 1