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a) 541 + (218 - x) = 735
\(\Rightarrow\) 218 - x = 735 - 541
\(\Rightarrow\) 218 - x = 194.
\(\Rightarrow\) x = 218 - 194
\(\Rightarrow\) x = 24
b) 5(x + 35) = 515
\(\Rightarrow\) x + 35 = 515 : 5 = 103.
\(\Rightarrow\) x = 103 - 35
\(\Rightarrow\) x =68.
c) 96 - 3(x + 1) = 42
\(\Rightarrow\) 3(x + 1) = 96 - 42 = 54
\(\Rightarrow\) x + 1 = 54 : 3
\(\Rightarrow\) x = 18 - 1
\(\Rightarrow\) x = 17
d) 12x - 33 = 32 . 33
\(\Rightarrow\) 12x - 33 = 243
\(\Rightarrow\)12x = 243 + 33
\(\Rightarrow\) 12x = 276.
\(\Rightarrow\) x = 23.
a) 541 + (218 - x) = 735
Suy ra 218 - x = 735 - 541 hay 218 - x = 194.
Do đó x = 218 - 194. Vậy x = 24.
b) 5(x + 35) = 515 suy ra x + 35 = 515 : 5 = 103.
Do đó x = 103 - 35 =68.
c) Từ 96 - 3(x + 1) = 42 suy ra 3(x + 1) = 96 - 42 = 54. Do đó x + 1 = 54 : 3 = 18. Vậy x = 18 - 1 hay x = 17.
d) Từ 12x - 33 = 32 . 33 hay 12x - 33 = 243 suy ra 12x = 243 + 33 hay 12x = 276. Vậy x = 23.
\(A=3+3^2+..+3^{24}\\ =\left(3+3^2\right)+\left(3^3+3^4\right)+...+\left(3^{23}+3^{24}\right)\\ =12+3^2\left(3+3^2\right)+....+3^{22}\left(3+3^2\right)\\ =12+3^2.12+...+3^{22}.12\\ =12\left(1+3^2+...+3^{22}\right)⋮12\)
a.
\(\frac{5^3\times90\times4^3}{25^2\times3^2\times2^{13}}=\frac{5^3\times5\times9\times2\times\left(2^2\right)^3}{\left(5^2\right)^2\times3^2\times2^{13}}=\frac{5^4\times3^2\times2\times2^6}{5^4\times3^2\times2^{13}}=\frac{1}{2^6}=\frac{1}{64}\)
b.
\(\frac{18\times27+18\times\left(-23\right)}{34\times4-4\times52}=\frac{18\times\left(27-23\right)}{4\times\left(34-52\right)}=\frac{18\times4}{4\times\left(-18\right)}=-1\)
c.
\(\frac{15^2\times16^4-15^3\times16^3}{12^2\times20^3-20^2\times12^3}=\frac{16^3\times15^2\times\left(16-15\right)}{12^2\times20^2\times\left(20-12\right)}=\frac{16\times\left(16\times15\right)^2}{8\times\left(20\times12\right)^2}=\frac{16\times240^2}{8\times240^2}=2\)
d.
\(\frac{2\times3+4\times6+14\times21}{3\times5+6\times10+21\times35}=\frac{2\times3\times\left(1+2\times2+7\times7\right)}{3\times5\times\left(1+2\times2+7\times7\right)}=\frac{2}{5}\)
Chúc bạn học tốt
a) \(\frac{5^3\cdot90\cdot4^3}{25^2\cdot3^2\cdot2^{13}}=\frac{5^3\cdot2\cdot3^2\cdot5\cdot2^6}{5^4\cdot3^2\cdot2^{13}}=\frac{1}{2^6}=\frac{1}{64}\)
b) \(\frac{18\cdot27+18\cdot\left(-23\right)}{34\cdot4-4\cdot52}=\frac{18\left(27-23\right)}{4\left(34-52\right)}=\frac{9\cdot4}{2\cdot\left(-18\right)}=\frac{3^2\cdot2^2}{2\cdot2\cdot3^2\cdot\left(-1\right)}=-1\)
c) \(\frac{15^2\cdot16^4-15^3\cdot16^3}{12^2\cdot20^3-20^2\cdot12^3}=\frac{15^2\cdot16^3\left(16-15\right)}{12^2\cdot20^2\left(20-12\right)}=\frac{15^2\cdot16^3}{12^2\cdot20^2\cdot8}=\frac{3^2\cdot5^2\cdot2^{12}}{2^4\cdot3^2\cdot2^4\cdot5^2\cdot2^3}=2\)
d) \(\frac{2\cdot3+4\cdot6+14\cdot21}{3\cdot5+6\cdot10+21\cdot35}=\frac{2\cdot3+2^2\cdot2\cdot3+2\cdot3\cdot7^2}{3\cdot5+2^2\cdot3\cdot5+3\cdot5\cdot7^2}=\frac{2\cdot3\left(1+2^2+7^2\right)}{3\cdot5\left(1+2^2+7^2\right)}=\frac{2}{5}\)
12x - 33 = 32 . 33
3 . 4x - 3 . 11 = 32+3
3 . (4x - 11) = 35
=> 4x - 11 = 35 : 3
4x - 11 = 34
4x - 11 = 81
4x = 81 + 11
4x = 92
x = 92 : 4
x = 23
12.x-33=3^2.3^3
12.x-33=243
12.x=243+33
12.x=276
x=276:12
x=23