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(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x (45200 – 1808 x 25)
=(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x (45200-45200)
=(12 + 77 + 34 + 23 + 88 + 45 + 55 + 66) x 0
=0
\(=\left[66+34+77+23+12+88+45+55\right]\times\left[1808\times\left(25-25\right)\right]\\ =0\)
(45+75)*66+(75+45)*34
=(45+75)*(66+34)
=120*100
=12000
11+22+33+44+55+66+77+88+99:11
=11+22+33+44+55+66+77+88+9
=(11+9)+(22+88)+(33+77)+(44+66)+55
=20+110*3+55
=20+330+55
=405
Ta có :
a, (45 + 75) x 66 + (75 + 45) x 34
= (45 + 75) x (66 + 34)
= 120 x 100
= 12000
11 + 22 + 33 + 44 + 55 + 66 + 77 + 88 + 99 : 11
= 33 + 77 + 121 + 165 + 9
= 405
\(a)\left(80\times96+40\times1808\right):1000\)
\(=\left(80\times96+40\times2\times904\right):1000\)
\(=\left(80\times96+80\times904\right):1000\)
\(=80\times\left(96+904\right):1000\)
\(=80\times1000:1000\)
\(=80\)
\(b)\) em xem lại đề xem có sai gì không em.
\(c)10\times12\times14\times16\times\left(88\times17-44\times34\right)\)
\(=10\times12\times14\times16\times\left(44\times2\times17-44\times2\times17\right)\)
\(=10\times12\times14\times16\times0\)
\(=0\)
a, \(\dfrac{90}{37}-\dfrac{38}{25}-\dfrac{8}{25}-\dfrac{4}{25}\)
= \(\dfrac{90}{37}\) - \(\dfrac{38+8+4}{25}\)
= \(\dfrac{90}{37}\) - 2
= \(\dfrac{16}{37}\)
\(\dfrac{24}{29}\) + \(\dfrac{32}{41}\) + \(\dfrac{34}{29}\) + \(\dfrac{50}{41}\)
=(\(\dfrac{24}{29}\) + \(\dfrac{34}{29}\)) + (\(\dfrac{32}{41}\) + \(\dfrac{50}{41}\))
= \(\dfrac{58}{29}\) + \(\dfrac{82}{41}\)
= 2 + 2
= 4
11 * 22 * 33 * 44 * 55 * 66 * 77 * 88 * 99 = ( Kết quả 1 ) 855652058110080
( Kết quả 2 ) ~ 8,5565205811008 x 1014
(11+99)+(22+88)+(33+77)+(44+66)+(55+55)=110+110+110+110+110=550
\(0,25+25\%\times55+\dfrac{1}{4}\times45-\dfrac{2}{8}\)
\(=\dfrac{1}{4}+\dfrac{1}{4}\times55+\dfrac{1}{4}\times45-\dfrac{1}{4}\)
\(=\dfrac{1}{4}\times\left(1+55+45-1\right)\)
\(=\dfrac{1}{4}\times100\)
\(=25\)
\(0,25+25\%\times55+\dfrac{1}{4}\times45-\dfrac{2}{8}\)
\(=\dfrac{1}{4}+\dfrac{1}{4}\times55+\dfrac{1}{4}\times45-\dfrac{1}{4}\)
\(=\dfrac{1}{4}\times1+\dfrac{1}{4}\times55+\dfrac{1}{4}\times45-\dfrac{1}{4}\times1\)
\(=\dfrac{1}{4}+\left(1+55+45-1\right)\)
\(=\dfrac{1}{4}\times100\)
\(=0,25\times100\)
\(=25\)
\(#:)\)
\(\text{a.61 x 23 + 39 x 22}\)
\(=61.22+1+39.22\)
\(=22.\left(61+39\right)+1\)
\(=22.100+1\)
\(=2200+1\)
\(=2201\)
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hok tốt
Giải:
( 12 + 77 + 34 + 23 + 88 + 45 + 55 + 66 ) . ( 45200 - 1808 .25 )
=( 12 + 77 + 34 + 23 + 88 + 45 + 55 + 66 ) . ( 45200 - 45200 )
=( 12 + 77 + 34 + 23 + 88 + 45 + 55 + 66 ) . 0
=0
Học tốt!!!
(12+77+34+23+88+45+55+66)* (45200-1808*25)
=(12+77+34+23+88+45+55+66)* (45200-45200)
=(12+17+34+23+88+45+55+66)* 0
=0