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`3/5 : x =1/3 +1/2`
` 3/5 : x= 2/6 +3/6`
` 3/5 : x= 5/6`
` x= 3/5 : 5/6`
` x= 3/5 xx 6/5`
` x= 18/25`
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`x: 7/15 =2`
` x= 2xx 7/15`
` x= 14/15`
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`x-3/2=11/4-5/4`
`x-3/2= 6/4`
`x= 3/2 +3/2`
`x= 6/2`
`x=3`
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`x+5/4 = 3/2+7/12`
`x+5/4 = 18/12+7/12`
`x+5/4 = 25/12`
`x= 25/12-5/4`
`x= 25/12- 15/12`
`x= 10/12`
`x= 5/6`
Câu 2:
\(\dfrac{7}{9}\cdot\dfrac{3}{35}=\dfrac{1}{5}\cdot\dfrac{1}{3}=\dfrac{1}{15}\)
\(\dfrac{9}{22}\cdot55=\dfrac{9\cdot55}{22}=\dfrac{9\cdot5}{2}=\dfrac{45}{2}\)
Bài 1 : Tìm x
12/5 - x : 5/7 = 12/5
x : 5/7 = 12/5 - 12/5
x : 5/7 = 0
x = 0 x 5/7
x = 0
Bài 2 :
Ta có : 5/7 = 25/35 ; 6/7 = 30/35
Vậy 4 phân số thỏa mãn là 26/35 ; 27/35 ; 28/35 ; 29/35
12/5 - x : 5/7 = 12/5 x:5/7=12/5-12/5 x:5/7=0 x=0.5/7=0
5/7 + 3/14 = 13/14
11/12 - 5/6 = 1/12
6 x 5/18 = 5/3
4/5 : 3/7 = 28/15
a. \(\frac{3}{4}\times x+\frac{5}{6}\times x-\frac{5}{2}=7\)
\(x\times\left(\frac{3}{4}+\frac{5}{6}\right)=7+\frac{5}{2}\)
\(x\times\left(\frac{9}{12}+\frac{10}{12}\right)=\frac{14}{2}+\frac{5}{2}\)
\(x\times\frac{19}{12}=\frac{19}{2}\)
\(x=\frac{19}{2}\div\frac{19}{12}\)
\(x=\frac{19}{2}\times\frac{12}{19}\)
\(x=6\)
b) \(12\times x-12\times84=0\)
\(12\times x=12\times84\)
\(x=84\)
`(y+2/9) xx 1/5 = 7/15`
`=> y +2/9 = 7/15 : 1/5`
`=> y +2/9 = 7/15 xx 5`
`=> y +2/9= 35/15`
`=> y= 35/15 -2/9`
`=> y= 7/3 -2/9`
`=> y= 21/9-2/9`
`=> y= 19/9`
Vậy `y=19/9`
__
`yxx(12/7 +4/3) = 5/6`
`=> y xx 64/21 = 5/6`
`=> y= 5/6 : 64/21`
`=> y=5/6 xx 21/64`
`=> y=35/128`
Vậy `y= 35/128`
\(\left(y+\dfrac{2}{9}\right)\times\dfrac{1}{5}=\dfrac{7}{15}\)
\(y+\dfrac{2}{9}=\dfrac{7}{15}:\dfrac{1}{5}\)
\(y+\dfrac{2}{9}=\dfrac{7}{15}\times5\)
\(y+\dfrac{2}{9}=\dfrac{7}{3}\)
\(y=\dfrac{7}{3}-\dfrac{2}{9}\)
\(y=\dfrac{21}{9}-\dfrac{2}{9}\)
\(y=\dfrac{19}{9}\)
========================
\(y\times\left(\dfrac{12}{7}+\dfrac{4}{3}\right)=\dfrac{5}{6}\)
\(y\times\left(\dfrac{36}{21}+\dfrac{28}{21}\right)=\dfrac{5}{6}\)
\(y\times\dfrac{64}{21}=\dfrac{5}{6}\)
\(y=\dfrac{5}{6}:\dfrac{64}{21}\)
\(y=\dfrac{5}{6}\times\dfrac{21}{64}\)
\(y=\dfrac{35}{128}\)
\(x+\frac{5}{6}=4\cdot\frac{5}{12}\) \(x\cdot\frac{5}{4}=2-\frac{4}{7}\)
\(x+\frac{5}{6}=\frac{5}{3}\) \(x\cdot\frac{5}{4}=\frac{10}{7}\)
\(x=\frac{5}{3}-\frac{5}{6}\) \(x=\frac{10}{7}:\frac{5}{4}\)
\(x=\frac{5}{6}\) \(x=\frac{8}{7}\)
a) X + 5/6 = 4 x 5/12
X + 5/6 = 5/3
X = 5/3 - 5/6
X = 5/6
X x 5/4 = 2 - 4/7
X x 5/4 = 10/7
X = 10/7 : 5/4
X = 10/7 x 4/5
X = 8/7
\(y.3\dfrac{7}{12}=6\dfrac{1}{4}\)
\(y.\dfrac{43}{12}=\dfrac{25}{4}\)
\(y=\dfrac{25}{4}:\dfrac{43}{12}\)
\(y=\dfrac{25.12}{4.43}\)
\(y=\dfrac{75}{43}\)
\(\left(\frac{12}{5}-x\right):\frac{5}{7}=\frac{12}{5}\)
\(\frac{12}{5}-x=\frac{12}{5}x\frac{5}{7}\)
\(\frac{12}{5}-x=\frac{12}{7}\)
\(x=\frac{12}{5}-\frac{12}{7}\)
\(x=\frac{24}{35}\)
\(\left(\frac{12}{5}-x\right):\frac{5}{7}=\frac{12}{5}\)
\(\frac{12}{5}-x=\frac{12}{5}\times\frac{5}{7}\)
\(\frac{12}{5}-x=\frac{12}{7}\)
\(x=\frac{12}{5}-\frac{12}{7}\)
\(x=\frac{24}{35}\)
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