Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a.\(\dfrac{17}{15}\div\dfrac{4}{3}=\dfrac{17}{20}\)
b.\(\dfrac{-12}{21}\div\dfrac{34}{43}=\dfrac{-86}{119}\)
c.\(\dfrac{-5}{9}\times\dfrac{3}{11}+\dfrac{13}{18}\times\dfrac{3}{11}\)
=\(\dfrac{3}{11}\times(\dfrac{-5}{9}+\dfrac{13}{18})=\dfrac{3}{11}\times\dfrac{1}{6}=\dfrac{1}{22}\)
d.\(\dfrac{-2}{9}\times\dfrac{5}{11}+\dfrac{-16}{9}\times\dfrac{5}{11}=\dfrac{5}{11}\times(\dfrac{-2}{9}+\dfrac{-16}{9})\)
=\(\dfrac{5}{11}\times(-2)=\dfrac{-10}{11}\)
\(=1+1+1+1+1+1+1+1+1+\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}\right)\)
\(=9+\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{9}-\dfrac{1}{10}\right)\)
=9+9/10=99/10
a: -146/43<0
0<1/89
=>-146/43<1/89
b: 21/23<1
1<13/12
=>21/23<13/12
\(2x+1+\frac{1}{6}+1+\frac{1}{12}+..+1+\frac{1}{90}=10\)
=> 2x + 8 + \(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}=10\)
=> 2x + \(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}=10-8\)
\(2x+1-\frac{1}{10}=2\)
=> 2x + \(\frac{9}{10}=2\)
=> 2x = 2 - 9/10
=>2x = 11/10
=> x = 11/10 : 2
x = 11/20
a)15/34-8/21+19/34-34/21
=(15/34+19/34)+(-8/21-34/21)
= 34/34+(-42/21)
=1+(-2)
=-1
đề tự ghi lại nha
=\(\left(\frac{15}{34}+\frac{19}{34}\right)+\left(\frac{-8}{21}-\frac{34}{21}\right)\)
=\(\frac{34}{34}+\frac{-42}{21}\)
=\(1+\left(-2\right)\)
=\(-1\)
\(-\dfrac{12}{21}\div\dfrac{34}{43}\)
\(=-\dfrac{12}{21}\times\dfrac{43}{34}\)
\(=-\dfrac{86}{119}\)
\(-\dfrac{12}{21}:\dfrac{34}{43}=-\dfrac{12}{21}.\dfrac{43}{34}=-\dfrac{2}{7}.\dfrac{43}{17}=-\dfrac{86}{119}\)