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4 tháng 2 2020
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1 tháng 4 2016
\(pt\Leftrightarrow \dfrac{3^x}{3}.\dfrac{4^x}{4}=12^{9-x}\Leftrightarrow 12^{x-1}=12^{9-x}\)
Suy ra x-1=9-x nên x=5
HN
5 tháng 7 2017
\(3^{x+1}-2^{2x+1}-12^{\dfrac{x}{2}}=0\)
\(\Leftrightarrow3.3^x-2.4^x-\sqrt{3^x.4^x}=0\)
\(\Leftrightarrow3.\dfrac{3^x}{4^x}-\sqrt{\dfrac{3^x}{4^x}}-2=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(\dfrac{3}{4}\right)^x=-\dfrac{2}{3}\left(l\right)\\\left(\dfrac{3}{4}\right)^x=1\end{matrix}\right.\)
\(\Rightarrow x=0\)
CM
23 tháng 8 2017
Điều kiện:
So với điều kiện, ta được tập nghiệm của phương trình là S = 3 2 ; 3 4 ; 7 8
Vậy phương trình đã cho có 3 nghiệm
Đáp án A
22 tháng 11 2016
\(2^x.3^{x-1}.5^{x+2}=12\\ \Leftrightarrow2^x.\frac{3^x}{3}.\left(5^x.25\right)=12\\ \Leftrightarrow\left(2.3.5\right)^x=\frac{36}{25}\\ \Leftrightarrow30^x=\frac{36}{25}\\\Leftrightarrow x=log_{30}\left(\frac{36}{25}\right)\)
Bạn chép đề có đúng không? Nếu sửa lại đề bài 1 tý thì nghiệm sẽ đẹp hơn
\(2^x.3^{x-1}.5^{x-2}=12\\ \Leftrightarrow2^x.\frac{3^x}{3}.\frac{5^x}{25}=12\\ \Leftrightarrow\left(2.3.5\right)^x=900\\ \Leftrightarrow30^x=900\Leftrightarrow x=2\)
bằng 96
lớp 12 À