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a)\(3^5.5^7.45=3^5.5^7.3^2.5=3^7.5^8\)
b)\(2^8.4^5.9^9\)\(=2^8.2^{10}.9^9=2^{18}.9^9\)
c)\(\left(2^3.3^5.5^7\right)^{10}.12^{20}=2^{13}.3^{15}.5^{17}.12^{20}\)\(=2^{13}.3^{15}.5^{17}.2^{40}.3^{20}=2^{53}.3^{35}.5^{17}\)
d)\(\left(x^2y\right)^5.\left(x^2y^2\right)^7.\left(x.y^2\right)^6.x^3=x^{10}.y^5.x^{14}.y^{14}.x^6.y^{12}.x^3\)
\(=x^{33}.y^{31}\)
e)\(18^{20}.45^5.5^{25}.8^{10}=2^{20}.3^{40}.5^5.3^{10}.5^5.5^{25}.2^{30}\)
\(=2^{50}.3^{50}.5^{35}=6^{50}.5^{35}\)
f)\(2^7.3^8.4^9.9^8=2^7.3^8.2^{18}.3^{16}=2^{25}.3^{24}\)
\(a,-7624+\left(1543+7624\right)-x=25\)
\(\Leftrightarrow-7624+9167-x=25\)
\(\Leftrightarrow1543-x=25\)
\(\Leftrightarrow x=1518\)
Vậy ................
\(b,\left(27-514\right)-\left(486-73\right)+x=7\)
\(\Leftrightarrow-487-413+x=7\)
\(\Leftrightarrow-900+x=7\)
\(\Leftrightarrow x=907\)
\(c,14-12+x=10-\left|-15\right|+\left|-3\right|\)
\(\Leftrightarrow2+x=10-15+3\)
\(\Leftrightarrow2+x=-2\)
\(\Leftrightarrow x=-4\)
Vậy ....
a) - 7624 + (1543 + 7624) - x = 25
-7624 + 9167 - x = 25
1543 - x = 25
x = 1543 - 25
x = 1518
b) (27 - 514) - (486 - 73) + x = 7
(-487) - 413 + x = 7
-900 + x = 7
x = 7 - (-900)
x = 907
c) 14 - 12 + x = 10 - |-15| + |-3|
14 - 12 + x = 10 - 15 + 3
14 - 12 + x = (-5) + 3
14 - 12 + x = -2
2 + x = -2
x = (-2) - 2
x = -4
\(A=\left|x+19\right|+\left|y-5\right|+2020\)
Ta có : \(\left|x+19\right|\ge0\forall x;\left|y-5\right|\ge0\forall y;2020>0\)
Suy ra : \(\left|x+19\right|+\left|y-5\right|+2020\ge2020\)
Dấu ''='' xảy ra : \(\hept{\begin{cases}x+19=0\\y-5=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=-19\\y=5\end{cases}}}\)
Vậy GTNN A = 2020 <=> x = -19 ; y = 5
a) (3^x-15)^7=0
=) 3x-15=0
=) 3x=15
=) x=5
b) 4^2.x-6=1
4^2.x-6= 4^0 ( vì số nào mũ không cũng bằng 1)
2x-6=0
2x=6
x=3
67-[8+7.\(3^2\)-24:6+\(\left(9-7\right)^3\)]:15
=67-[8+63-4+8]:15
=67-75:15
=67-5
=62
67 -[ 8 + 7 x 32 - 24: 6 + (9 - 7 )3] :15
= 67 -[ 8 + 7 . 32 - 24 : 6 + 23 ] : 15
= 67 - [ 8 + 7 . 9 - 24 : 6 + 8 ] : 15
= 67 - [ 71 - 12 ] : 15
= 67 - 59 : 15
= 8 : 15
=> ko thực hiện đc .
\(\left(4\frac{46}{65}+x\right).1\frac{1}{12}=5,75\)
\(\Rightarrow\frac{306}{65}+x.\frac{13}{12}=\frac{23}{4}\)
\(\Rightarrow\frac{51}{10}+\frac{13}{12}x=\frac{23}{4}\)
\(\Rightarrow306x=65x=345\)
\(\Rightarrow65x=39\)
\(\Rightarrow x=\frac{3}{5}\)
b, \(\frac{5}{4}-\left(\frac{3}{2}x+0,5\right)=1\frac{1}{4}\)
\(\Rightarrow\frac{5}{4}-\frac{3}{2}x-0,5=\frac{5}{4}\)
\(\Rightarrow\frac{5}{4}-\frac{3}{2}x-\frac{1}{2}=\frac{5}{4}\)
\(\Rightarrow\frac{3}{4}-\frac{3}{2}x=\frac{5}{4}\)
\(\Rightarrow3-6x=5\)
\(\Rightarrow-6x=2\)
\(\Rightarrow x=-\frac{1}{3}\)
Phần b) chị sai nhé ! Dấu [ ] là phần nguyên nâng cao của lớp 6 nhé.