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=(1/1-1/2)+(1/2-1/3)+(1/4-1/5)+(1/5-1/6)+(1/6-1/7) =(1/2-1/2)+(1/3-1/3)+(1/4-1/4)+(1/5-1/5)+(1/6-1/6)+(1/1-1/7) = 0+0+0+0+0+6/7 =6/7
= 1/1.2 + 1/2.3 + 1/3.4 + 1/4.5 + 1/5.6
= 1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6
= 1-1/6 = 5/6
k mk nha
\(\frac{1}{2}\)+\(\frac{1}{6}\)+\(\frac{1}{12}\)+\(\frac{1}{20}+\frac{1}{30}\)=\(\left(\frac{6}{12}+\frac{2}{12}+\frac{1}{12}\right)\)+\(\left(\frac{30}{60}+\frac{20}{60}\right)\)
= \(\frac{9}{12}+\frac{50}{60}\)
=\(\frac{45}{60}+\frac{50}{60}\)
=\(\frac{95}{60}\)
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}\)
= \(\frac{6}{12}+\frac{2}{12}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}\)
= \(\frac{8}{12}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}\)
= \(\frac{9}{12}+\frac{1}{20}+\frac{1}{30}\)
= \(\frac{4}{5}+\frac{1}{30}\)
= \(\frac{24}{30}+\frac{1}{30}\)
= \(\frac{25}{30}=\frac{5}{6}\)
Chúc bạn hok tốt !
1/2 + 1/6 + 1/12 + 1/20 + 1/30
= 1/1.2 + 1/2.3 + 1/3.4 + 1/4.5 + 1/5.6
= 1/1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6
= 1 - 1/6
= 5/6
Đúng cho mình nha
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}\)
=\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{4.3}+\frac{1}{4.5}+\frac{1}{5.6}\)
=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
=\(1-\frac{1}{6}\)
=\(\frac{5}{6}\)
\(M=\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{6.7}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{6}-\dfrac{1}{7}=1-\dfrac{1}{7}=\dfrac{6}{7}\)
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{42}=\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{6\times7}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{6}-\frac{1}{7}=1-\frac{1}{7}=\frac{6}{7}\)
\(\frac{1}{2} +\frac{1}{6}+\frac{1}{21}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}=\frac{23}{28}\)
Gọi tổng trên là A
A = 1/1.2 + 1/2.3 + 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7
A = 1 - 1/2 + 1/2 - 1/3 +.......+ 1/6 - 1/7
A = 1 - 1/7
A = 6/7
1/2+1/6+1/12+1/20+1/30+1/42
=1/1.2+1/2.3+1/3.4+1/4.5+1/5.6+1/6.7
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7
=1-1/7=7-1/7=6/7
1/42 + 1/30 + 1/20 + 1/12 + 1/6 + 1/2
= 1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42
= 1/1.2 + 1/2.3 + 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7
= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7
= 1 - 1/7
= 6/7
Chú ý : Dấu " . " là dấu x
= 1/1x2+1/2x3+1/3x4+1/4x5+1/5x6+1/6x7
= 1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7
= 1-1/7
= 6/7
\(S=\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}\)
\(=\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+\dfrac{1}{5.6}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}\)
\(=1-\dfrac{1}{6}=\dfrac{5}{6}\)
\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}\)
\(=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+\dfrac{1}{5\cdot6}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}\)
\(=1-\dfrac{1}{6}=\dfrac{5}{6}\)
#Ayumu