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8 tháng 12 2016

\(\frac{1}{2}\)+\(\frac{1}{6}\)\(\frac{1}{12}\)+\(\frac{1}{20}\)+\(\frac{1}{30}\)+\(\frac{1}{42}\)+\(\frac{1}{56}\)=\(\frac{7}{8}\)

8 tháng 12 2016

1/2+1/6+1/12+1/20+1/30+1/42+1/56=7/8=0.875

kick mik nha xin đó

6 tháng 6 2016

1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56

= 1/1x2 + 1/2x3 + 1/3x4 + 1/4x5 + 1/5x6 + 1/6x7 + 1/7x8

= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8

= 1 - 1/8

= 7/8

6 tháng 6 2016

1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56

= 1/1x2 + 1/2x3 + 1/3x4 + 1/4x5 + 1/5x6  + 1/6x7 + 1/7x8

= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/7 - 1/8

= 1 - 1/8

= 7/8

29 tháng 5 2016

1/2+1/6+1/12+1/20+1/30+1/42+1/56=7/8

29 tháng 5 2016

A=1/2.3+1/3.4+1/4.5+1/5.6+1/6.7+1/7.8+1/8.9+1/9.10+1/10.11

A=1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10+1/10-1/11

A=1/2-(1/3-1/3)-(1/4-1/4)-(1/5-1/5)-(1/6-1/6)-(1/7-1/7)-(1/8-1/8)-(1/9-1/9)-(1/10-1/10)-1/11

A=1/2-1/11 A=11/22-2/22

A=9/22 

\(A=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}\)

\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\)

\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)

\(A=1-\frac{1}{8}\)

\(A=\frac{7}{8}\)

29 tháng 8 2016

\(A=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}\)

\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}\)

\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}\)

\(A=1-\frac{1}{8}\)

\(A=\frac{7}{8}\)

1 tháng 8 2019

đề lạ thế

27 tháng 7 2015

1/2+1/6+...+1/72=1/1x2+1/2x3+...+1/8x9=1/1-1/2+1/2-1/3+...+1/8-1/9=1-1/9=8/9

24 tháng 6 2015

\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\)

\(=\frac{1}{1}+\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-..........-\frac{1}{8}+\frac{1}{9}\)

\(=\frac{1}{1}-\frac{1}{9}\)

\(=\frac{8}{9}\)

Mình giải đúng đó

 

18 tháng 7 2015

\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{90}+\frac{1}{110}\)

\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{9.10}+\frac{1}{10.11}\)

=\(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...\frac{1}{7}-\frac{1}{8}+\frac{1}{9}-\frac{1}{10}+\frac{1}{10}-\frac{1}{11}\)

\(=1-\frac{1}{8}+\frac{1}{9}-\frac{1}{11}\)

\(=\frac{709}{792}\)

11 tháng 9 2020

( 1/90 + 1/72 + ... + 1/2)
= - { 1/( 9.10) + 1/(9.8) + ... + 1/( 2.1)}
= - ( 1/9 - 1/10 + 1/8 - 1/9 + ...+ 1 - 1/2) ( 1/90 = 1/(9.10) = 1/9 - 1/10)
= - ( 1 - 1/10)
= -9/10

30 tháng 6 2020

\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\)

\(=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+.....+\frac{1}{9\cdot10}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+.....+\frac{1}{9}-\frac{1}{10}\)

\(=1-\frac{1}{10}=\frac{9}{10}\)

1 tháng 7 2020

\(\frac{1}{2}+\frac{1}{6}+.......+\frac{1}{90}\)

\(=\frac{1}{1.2}+\frac{1}{2.3}+....+\frac{1}{9.10}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...-\frac{1}{10}\)

=\(1-\frac{1}{10}\)

\(=\frac{9}{10}\)