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\(\frac{2}{x}=\frac{y}{15}=\frac{\left(-25\right)}{75}\)
\(\Rightarrow\frac{y}{15}=\frac{\left(-1\right)}{3}\)
\(\frac{y}{15}=\frac{\left(-5\right)}{15}\)
\(\Rightarrow15y=15\times\left(-5\right)\)
\(15y=\left(-75\right)\)
\(y=\left(-75\right)\div15\)
\(y=\left(-5\right)\)
\(\Rightarrow\frac{2}{x}=\frac{\left(-5\right)}{15}\)
\(\frac{2}{x}=\frac{\left(-1\right)}{3}\)
\(\Rightarrow-x=3\times2\)
\(-x=6\)
\(x=\left(-6\right)\)
\(V\text{ậy}x=\left(-6\right);y=\left(-5\right)\)
a) Ta có: \(\left|-5\right|+\left|x-1\right|=\left|7\right|\)
\(\Leftrightarrow\left|x-1\right|+5=7\)
\(\Leftrightarrow\left|x-1\right|=2\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=2\\x-1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)
Vậy: \(x\in\left\{3;-1\right\}\)
b) Ta có: \(2\cdot\left|2x-4\right|-\left|-4\right|=\left|-50\right|\)
\(\Leftrightarrow4\cdot\left|x-2\right|-4=50\)
\(\Leftrightarrow4\cdot\left|x-2\right|=54\)
\(\Leftrightarrow\left|x-2\right|=\dfrac{27}{2}\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=\dfrac{27}{2}\\x-2=-\dfrac{27}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{31}{2}\left(loại\right)\\x=-\dfrac{23}{2}\left(loại\right)\end{matrix}\right.\)
Vậy: \(x\in\varnothing\)
a, | -5 | + | x-1 | = | 7 |
5 + | x - 1 | = 7
| x - 1 | = 2
TH1 x -1 = 2
x = 3
TH2 x -1 = -2
x= -1
2/3.x + 1/4 = 7/12
2/3.x = 7/12 - 1/4
2/3.x = 1/3
x = 1/3 : 2/3
x = 1/2
Bài làm
\(\frac{2}{3}x+\frac{1}{4}=\frac{7}{12}\)
\(\frac{2}{3}x=\frac{7}{12}-\frac{1}{4}\)
\(\frac{2}{3}x=\frac{7}{12}-\frac{3}{12}\)
\(\frac{2}{3}x=\frac{4}{12}\)
\(\frac{2}{3}x=\frac{1}{3}\)
\(x=\frac{1}{3}:\frac{2}{3}\)
\(x=\frac{1}{3}.\frac{3}{2}\)
\(x=\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\)
`@` `\text {Ans}`
`\downarrow`
\(\left(\dfrac{x}{3}+\dfrac{1}{2}\right)\left(75\%-1\dfrac{1}{2}x\right)=0\)
`=>`\(\left[{}\begin{matrix}\dfrac{x}{3}+\dfrac{1}{2}=0\\\dfrac{75}{100}-\dfrac{3}{2}x=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}\dfrac{x}{3}=-\dfrac{1}{2}\\\dfrac{3}{2}x=\dfrac{75}{100}\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}2x=-1\cdot3\\x=\dfrac{75}{100}\div\dfrac{3}{2}\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}2x=-3\\x=\dfrac{1}{2}\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=-\dfrac{3}{2}\\x=\dfrac{1}{2}\end{matrix}\right.\)
Vậy, `x={-3/2; 1/2}.`
\(\left(50\%x+\frac{9}{4}\right):\frac{-2}{3}=\frac{17}{6}\)
\(\left(\frac{1}{2}x+\frac{9}{4}\right):\frac{-2}{3}=\frac{17}{6}\)
\(\frac{1}{2}x+\frac{9}{4}=\frac{17}{6}.\frac{-2}{3}\)
\(\frac{1}{2}x+\frac{9}{4}=\frac{-17}{9}\)
\(\frac{1}{2}x=\frac{-17}{9}-\frac{9}{4}\)
\(\frac{1}{2}x=\frac{-149}{36}\)
\(x=\frac{-149}{36}:\frac{1}{2}\)
\(x=\frac{-149}{18}\)
~ Hok tốt ~
a) Bấm máy là ra (mình chỉ giải câu b)
b) (50%x+ 9/4) : -2/3=17/6
<=> (1/2x + 9/4) = 17/9
<=> 1/2x= 17/9 - 9/4
<=> 1/2x = -13/36
<=> x= -13/72
\(\Leftrightarrow x^2-2x+1-1=0\)
\(\Leftrightarrow\left(x-1\right)^2=1\Rightarrow\left(x-1\right)=\pm1\Rightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)
( 15-x ) + 2x = 2016-4
( 15-x ) + 2x = 2012
15-x + 2x = 2012
Vì - x + 2x = x nên có :
15 + x = 2012
x = 2012 - 15
x = 1997
(15-x)+2x=2016-2
(15-x)+2x=2012
15x1-Xx1=2012
1(15-x)=2012
15-x=2012:1
15-x=2012=>x=15-2012=-1997
100 - 50:(x-4)=75
50:(x-4)= 100 - 75
50:(x-4)=25
x-4= 50:25
x-4=2
x=2+4
x=6
6 nhaa