Question

[Takitori]

1. Tính

a) \(\frac{-17}{30}-\frac{11}{-15}+\frac{-7}{12}\)

b) \(\frac{-5}{9}+\frac{5}{9}:\left(1\frac{2}{3}-2\frac{1}{12}\right)\)

Answer 1

[❤P͟͟.T͟͟↭2K͟͟7➻❥]

a)\(\frac{-17}{30}-\frac{11}{-15}+\frac{-7}{12}=\frac{-17}{30}-\frac{22}{-30}+\frac{-7}{12}\)

= \(\frac{-39}{30}+\frac{-7}{12}=\frac{-78}{60}+\frac{-35}{60}\)

= \(\frac{-113}{60}\)

b)\(\frac{-5}{9}+\frac{5}{9}:\left(1\frac{2}{3}-2\frac{1}{12}\right)\)

=\(\frac{-5}{9}+\frac{5}{9}:\left(\frac{5}{3}-\frac{25}{12}\right)\)

= \(\frac{-5}{9}+\frac{5}{9}:\left(\frac{20}{12}-\frac{25}{12}\right)\)

= \(\frac{-5}{9}+\frac{5}{9}:\frac{-5}{12}=\frac{-5}{9}+\frac{4}{-3}\)

=\(\frac{-5}{9}+\frac{12}{-9}=\frac{-5}{9}+\frac{-12}{9}=\frac{-17}{9}\)

chúc bn học tốt !