Question

[kagome]

1 tim x

2346:(25+x)=23

2(x-3)+5(x+4)=49

(2x-10)³.25¹⁰⁰⁷=5².5²⁰¹⁵

Answer 1

[Nguyễn Ngọc Quý]

2346 : (25 + x) = 23

=> 25 + x = 2346 : 23 = 102

=> x = 102 - 25  =  77

Vậy x = 77

2(x-3) + 5(x+4) = 49

=> 2x - 6 + 5x + 20 = 49

=> 7x + (20 - 6) = 49

=> 7x + 14 = 49

=> 7x = 49 - 14 = 35

=> x = 35 : 7 = 5

Vậy x = 5

(2x-10)³ . 25¹⁰⁰⁷ = \(5^2.5^{2015}\)

\(\left(2x-10\right)^3.5^{2014}=5^{2014}.5^3\)

\(\left(2x-10\right)^3=5^3\)

2x - 10 = 5

=> 2x = 5 + 10 = 15

=> x = 15  2 = 7,5

Vậy x = 7,5

Answer 2

[Minh Hiền]

1. a. 2346:(25+x)=23

=> 25+x=2346:23

=> 25+x=102

=> x=102-25

=> x=77

b. 2(x-3)+5(x+4)=49

=> 2x-6+5x+20=49

=> 7x+14=49

=> 7x=49-14

=> 7x=35

=> x=35:7

=> x=5

c. (2x-10)³.25¹⁰⁰⁷=5².5²⁰¹⁵

=> (2x-10)³.(5²)¹⁰⁰⁷=5²⁰¹⁷

=> (2x-10)³.5²⁰¹⁴=5²⁰¹⁷

=> (2x-10)³=5²⁰¹⁷:5²⁰¹⁴

=> (2x-10)³=5³

=> 2x-10=5

=> 2x=5+10

=> 2x=15

=> x=15:2

=> x=7,5