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A
\(\frac{3}{5}\div\frac{4}{5}+\frac{1}{2}\times\frac{2}{3}\)
\(=\frac{3}{4}+\frac{1}{3}\)
\(=\frac{13}{12}\)
B
\(\frac{5}{4}\times x=\frac{3}{8}+\frac{1}{4}\)
\(\frac{5}{4}\times x =\frac{5}{8}\)
\(x=\frac{5}{8}\div\frac{5}{4}\)
\(x=\frac{4}{8}=\frac{1}{2}\)
\(\frac{2}{5}\div\frac{x}{5}=\frac{1}{5}\)
\(\Leftrightarrow\frac{2}{5}\times\frac{5}{x}=\frac{1}{5}\)
\(\Leftrightarrow\frac{2}{x}=\frac{1}{5}\)
\(\Leftrightarrow1\times x=2\times5\)
\(\Leftrightarrow x=10\)
2/5 : x/5= 1/5
X/5= 2/5 : 1/5
X/5 = 10/5
Vậy x= 10
1: \(=\dfrac{1}{3}\cdot\dfrac{3}{7}\cdot\dfrac{1}{2}=\dfrac{1}{7\cdot2}=\dfrac{1}{14}\)
2: =5/12+1/7
=35/84+12/84=47/84
3: =8(8/9-6/9)
=8*2/9=16/9
4: \(=\dfrac{5}{12}\cdot\dfrac{12}{5}=1\)
5: =16/5+6
=16/5+30/5=46/5
6: =10*1/2-10*1/5
=5-2=3
25 - ( x - \(\frac{2}{5}\) ) : \(\frac{1}{2}\) = 1
( x - \(\frac{2}{5}\) ) : \(\frac{1}{2}\) =25-1
( x - \(\frac{2}{5}\) ) : \(\frac{1}{2}\) =24
( x - \(\frac{2}{5}\) ) =24x \(\frac{1}{2}\)
( x - \(\frac{2}{5}\) ) = 12
x =12 + \(\frac{2}{5}\)
x =\(\frac{62}{5}\)