Question

[Phạm Quỳnh Anh]

1 TÌM GIÁ TRỊ NHỎ NHẤT CỦA B = | x-3| + |x-2|

2TÌM x BIẾT:
a, |x-2| -3 = -7
b, |x-5| + 3=8
c, |x+3| -2+2x= 5
d, |x-3,1|+ |y-1,2| =0

3TÍNH
a, (-2,7 )+(-3,5) -1,2 .(-2)
b, (-2,3) .(-0,4) -(-3,1) . (-2,1) -13,2

Answer 1

[B.Thị Anh Thơ]

Bài 2:

a,\(|x-2|-3=-7\)

\(\Rightarrow|x-2|=-4\)

\(\Rightarrow x\in\varnothing\)

b,\(|x-5|+3=8\)

\(\Rightarrow|x-5|=5\)

\(\Rightarrow\left[{}\begin{matrix}x-5=5\\x-5=-5\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=10\\x=0\end{matrix}\right.\)

c,\(|x+3|-2+2x=5\)

\(\Rightarrow|x+3|+2x=7\)

\(\Rightarrow\left[{}\begin{matrix}x+3=2x=7,x+3\ge0\\-\left(x+3\right)+2x=7,x+3< 0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\frac{4}{3}\\x=10,x< -3\end{matrix}\right.,x\ge-3\)

\(\Rightarrow\left[{}\begin{matrix}x=\frac{4}{3}\\x\in\varnothing\end{matrix}\right.\)

d,\(|x-3,1|+|y-1,2|=0\)

Thay y =0

\(\Rightarrow|x-3,1|+|0-1,2|=0\)

\(\Rightarrow|x-3,1|+|-1,2|=0\)

\(\Rightarrow|x-3,1|+1,2=0\)

\(\Rightarrow|x-3,1|=-1,2\)

\(\Rightarrow x\in\varnothing\)

Answer 2

[B.Thị Anh Thơ]

Bài 3:

a,(-2,7)+9-3,5)-1,2(-2)

=>-2,7-3,5+2,4

=>-3,8

b, (-2,3)(-0,4)-(-3,1)(-2,1)-13,2

=>0,92+3,1(-2,1)-13,2

=>0,92-6,51-13,2

=-18,79