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Câu 1:
\(\frac{5^4.18^4}{125.9^5.16}\) = \(\frac{5^4.\left(2.9\right)^4}{5^3.9^5.2^4}\) = \(\frac{5^4.2^4.9^4}{5^3.9^5.2^4}\) = \(\frac{5}{9}\)
Câu 2:
\(\frac{\left(-5\right)^{32}.20^{43}}{\left(-8\right)^{29}.125^{25}}\) = \(\frac{5^{32}.\left(4.5\right)^{43}}{\left(-2.4\right)^{29}.\left(5^3\right)^{25}}\) = \(\frac{5^{32}.4^{43}.5^{43}}{\left(-2\right)^{29}.4^{29}.5^{75}}\) = \(\frac{4^{14}.5^{43}}{\left(-2\right)^{29}.5^{43}}\)
=\(\frac{4^{14}}{\left(-2\right)^{29}}\) = = \(\frac{\left[-2.\left(-2\right)\right]^{14}}{\left(-2\right)^{29}}\) = \(\frac{\left(-2\right)^{14}.\left(-2\right)^{14}}{\left(-2\right)^{29}}\) = \(\frac{\left(-2\right)^{14}}{\left(-2\right)^{15}}\) = \(\frac{-1}{2}\)
Câu 1:
a, 4.(-5)2+(-2)3.25
<=>-4.52-8.52
=>52.(-4-8)
=>25.(-32)
=>-800
Chúc bạn học tốt!
\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-......+\frac{1}{99}\)-\(\frac{1}{100}\)
\(\Rightarrow\)\(1-\frac{1}{100}\)
=99/100
a) \(\frac{99}{100}\)
b)\(\frac{11}{24}\)
3) x=\(\frac{27}{2}\)
y=\(\frac{-10}{3}\)
a, \(\frac{2}{3}-\frac{5}{3}\)
\(=\frac{2-5}{3}\)
\(=\frac{-3}{3}=-1\)
b, \(\left(4:\frac{4}{3}-\frac{1}{2}\right)x\)\(\frac{6}{5}\)\(-17\)
-> Tự làm,dễ mà?
1.
a. \(\frac{5^4.18^4}{125.9^5.16}=\frac{5^4.2^4.3^8}{5^3.3^{10}.2^4}=\frac{5}{3^2}=\frac{5}{9}\)
2.
a . x : ( 0,25 ) 4 = ( 0,5 ) 2
=> x : ( 0,5 ) 8 = ( 0,5 ) 2
=> x = ( 0,5 ) 2 . ( 0,5 ) 8
=> x = ( 0,5 ) 10
=> x = \(\frac{1}{1024}\)
Bài 1.\(\frac{5^4\cdot18^4}{125\cdot9^5\cdot16}=\frac{5^4\cdot9^4\cdot2^4}{5^3\cdot9^5\cdot2^4}=\frac{5}{9}\)