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Bài 1:
a) \(2\cdot3\cdot2\cdot3\cdot2\cdot3=2^3\cdot3^3=6^3\)
b) \(100\cdot100\cdot100=100^3=\left(10^2\right)^3=10^6\)
c) \(2x\cdot2x\cdot2x=\left(2x\right)^3=8x^3\)
d) \(2\cdot2^3\cdot2^5=2^{1+3+5}=2^9\)
e) \(3^{10}\cdot3^5\cdot3^4=3^{10+5+4}=3^{19}\)
Bài 2:
\(40-x=2^6\cdot2^2\)
\(\Rightarrow40-x=2^8\)
\(\Rightarrow40-x=256\)
\(\Rightarrow x=40-256\)
\(\Rightarrow x=-216\)
b) \(3^2\cdot3^x=81\)
\(\Rightarrow3^{2+x}=3^4\)
\(\Rightarrow2+x=4\)
\(\Rightarrow x=4-2=2\)
c) \(2^x=512\)
\(\Rightarrow2^x=2^9\)
\(\Rightarrow x=9\)
d) \(x^5=243\)
\(\Rightarrow x^5=3^5\)
\(\Rightarrow x=3\)
Bài 3:
a) \(3^6=3\cdot3\cdot3\cdot3\cdot3\cdot3=729\)
b) \(8^3=\left(2^3\right)^3=2^9=512\)
c) \(3^3\cdot75+3^3\cdot25=3^3\cdot\left(75+25\right)=3^3\cdot100=27\cdot100=2700\)
d) \(2^3\cdot3-\left(1^{10}+8\right):3=2^3\cdot3-9:3=2^3\cdot3-3\cdot3:3=3\cdot\left(2^3-3:3\right)=3\cdot\left(8-1\right)=21\)
e) \(32-\left[4+\left(5\cdot3^2-42\right)\right]-14=18-\left[4+\left(45-42\right)\right]\)
\(=18-\left(4+3\right)\)
\(=18-7=11\)
2:
a: =>40-x=256
=>x=40-256=-216
b: =>x+2=4
=>x=2
c: =>2^x=2^9
=>x=9
d; =>x^5=3^5
=>x=3
\(\Rightarrow2^{x+1}=16=2^4\\ \Rightarrow x+1=4\\ \Rightarrow x=3\)
\(A=\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{100}\)
\(\Rightarrow A=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}...+\dfrac{1}{99}-\dfrac{1}{100}\)
\(\Rightarrow A=1-\dfrac{1}{100}\)
\(\Rightarrow A=\dfrac{99}{100}\)
Đoạn suy ra đầu tiên cơ sở gì bạn suy ra được như vậy nhỉ?
=1/2+1/3+1/4+...+1/100
xét mẫu:có ssh là (100-2):1+1=99 số
tổng là (100+2)*99:2=5940
vậy ta có 1/5940
\(\left(\frac{1}{2}-1\right)\times\left(\frac{1}{3}-1\right)\times\left(\frac{1}{4}-1\right)\times...\times\left(\frac{1}{1963}-1\right)\)
\(=\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times\left(1-\frac{1}{4}\right)\times...\times\left(1-\frac{1}{1963}\right)\)
\(=\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times...\times\frac{1962}{1963}\)
\(=\frac{1}{1963}\)
a) x - 1/2 = 3/5
x = 3/5 + 1/2
x = 11/10
b) x - 1/2 = -2/3
x = -2/3 + 1/2
x = -1/6
c) 2/5 - x = 0,25
x = 2/5 - 0,25
x = 2/5 - 1/4
x = 3/20
`a)25/(x+1)-1 1/6=-1/3-0,5`
`=>25/(x+1)=-1/3-1/2+1+1/6`
`=>25/(x+1)=1/3`
`=>75=x+1`
`=>x=74`
Vậy `x=74`
`b)(2x+25 3/5)^2-9/25=0`
`=>(2x+128/5)=9/25`
`**2x+128/5=3/5`
`=>2x=-125/5=-25`
`=>x=-25/2`
`**2x+128/5=-3/5`
`=>2x=-131/5`
`=>x=-131/10`
a) 1 + 3 + 5 + ... + 13
= (13 + 1).[(13 - 1) : 2 + 1] : 2
= 14 . 7 : 2
= 49
= 7²
b) 3² + 4² + 12²
= 9 + 16 + 144
= 169
= 13²
21
21 nhea Pạn