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\(a,\left(\frac{3}{8}+-\frac{3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
= \(\left(-\frac{3}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
= \(\frac{5}{24}:\frac{5}{6}+\frac{1}{2}\)
= \(\frac{1}{4}+\frac{1}{2}\)
= \(\frac{3}{4}\)
b)\(-\frac{7}{3}.\frac{5}{9}+\frac{4}{9}.\left(-\frac{3}{7}\right)+\frac{17}{7}\)
=\(-\frac{35}{27}+\left(-\frac{4}{21}\right)+\frac{17}{7}\)
= \(-\frac{35}{27}+\frac{47}{21}\)
= \(\frac{178}{189}\)
c) \(\frac{117}{13}-\left(\frac{2}{5}+\frac{57}{13}\right)\)
= \(\frac{117}{13}-\frac{311}{65}\)
= \(\frac{274}{65}\)
d) \(\frac{2}{3}-0,25:\frac{3}{4}+\frac{5}{8}.4\)
= \(\frac{2}{3}-\frac{1}{4}:\frac{3}{4}+\frac{5}{8}.4\)
= \(\frac{2}{3}-\frac{1}{3}+\frac{5}{2}\)
= \(\frac{1}{3}+\frac{5}{2}\)
= \(\frac{17}{6}\)
4 câu đầu hìn như sai đề :v
`m)(3/2-2/(-5)):x-1/2=3/2`
`<=>(3/2+2/5):x=3/2+1/2=2`
`<=>19/10:x=2`
`<=>x=19/10:2=19/20`
`n)(3/2-5/11-3/13)(2x-2)=(-3/4+5/22+3/26)`
`<=>(3/2-5/11-3/13)(2x-2)+3/4-5/22-3/26=0`
`<=>(3/2-5/11-3/13)(2x-2)+1/2(3/2-5/11-3/13)=0`
`<=>(3/2-5/11-3/13)(2x-2+1/2)=0`
Mà `3/2-5/11-3/13>0`
`<=>2x-2+1/2=0`
`<=>2x-3/2=0`
`<=>2x=3/2<=>x=3/4`
a) -4/5 + 5/2x = -3/10
5/2x = -3/10 + 4/5
5/2x = 1/5
5/2x = 1/2
x = 1/2 : 5/2
x = 1/5
b) 4/3 + 5/8 : x = 1/12
5/8x = 1/12 - 4/3
5/8x = -5/4
5 = -5/4.8x
5 = -10x
5/-10 = x
-1/2 = x
x = -1/2
c) (x - 1/3)(x - 2/5) = 0
x - 1/3 = 0 hoặc x - 2/5 = 0
x = 0 + 1/3 x = 0 + 2/5
x = 1/3 x = 2/5
\(\left(2x-3\right)\left(\dfrac{5}{2}-x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x-3=0\\\dfrac{5}{2}-x=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}2x=3\\x=\dfrac{5}{2}-0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=\dfrac{5}{2}\end{matrix}\right.\)
\(x-12=\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{1}{2}+12\Rightarrow x=\dfrac{25}{2}\)
\(\left(2x+\dfrac{3}{5}\right)^2-\dfrac{9}{25}=0\)
\(\Rightarrow\left(2x+\dfrac{3}{5}\right)^2=\left(\pm\dfrac{3}{5}\right)^2\Rightarrow\left[{}\begin{matrix}2x+\dfrac{3}{5}=\dfrac{3}{5}\\2x+\dfrac{3}{5}=-\dfrac{3}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{3}{5}\end{matrix}\right.\)
\(\dfrac{7}{3}x-\dfrac{5}{2}x=-\dfrac{1}{3}\)
\(\Rightarrow\left(\dfrac{7}{3}-\dfrac{5}{2}\right)x=-\dfrac{1}{3}\Rightarrow-\dfrac{1}{6}x=-\dfrac{1}{3}\Rightarrow x=2\)
\(\dfrac{3}{4}+\dfrac{1}{4}:x=1\)
\(\Rightarrow\dfrac{1}{4}:x=\dfrac{1}{4}\Rightarrow x=1\)
\(\dfrac{1}{3}+\dfrac{2}{5}.\left(x+1\right)=1\)
\(\Rightarrow\dfrac{1}{3}+\dfrac{2}{5}x+\dfrac{2}{5}=1\Rightarrow\dfrac{2}{5}x=\dfrac{4}{15}\Rightarrow x=\dfrac{2}{3}\)