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a)\(\text{ 4x - 15 = -75 - x}\)
\(4x-15+75+x=0\)
\(5x+60=0\)
\(5x=-60\)
\(x=-14\)
Vậy....
Thêm dấu suy ra trc mỗi dòng nha
Học tốt
-x + 20 = - (-15) - (8) + 13
-x + 20 = 15 - 8 + 13
-x + 20 = 7 + 13
- x + 20 = 20
x = 20 - 20
x = 0
-(-10) + x = -13 + (-9) + (-6)
10 + x = -13 - 9 - 6
10 + x = -28
x = -28 - 10
x = -38
1)\(25⋮\left(2x-3\right)\Leftrightarrow25+3⋮2x\Leftrightarrow28⋮2x\Leftrightarrow x=14\)
1: \(\Leftrightarrow2x-3\in\left\{1;-1;5;-5;25;-25\right\}\)
hay \(x\in\left\{2;1;4;14\right\}\)
2: \(\Leftrightarrow4x+1+12⋮4x+1\)
=>\(4x+1\in\left\{1;-1;2;-2;3;-3;4;-4;6;-6;12;-12\right\}\)
hay \(x\in\left\{0\right\}\)
3: \(x< =6\)
nên 3x<=18
=>3x-1<=17
mà 3x-1 chia hết cho 2
nên \(3x-1\in\left\{0;2;4;6;8;10;12;14;16\right\}\)
=>\(3x\in\left\{3;9;15\right\}\)
=>\(x\in\left\{1;3;5\right\}\)
1-2+3-4+5-6+...+2009-2010+2011
= ( 1 - 2 ) + (3-4) + ( 5-6) +...+ (2009- 2010)+2011
= (-1) + (-1) + (-1) + ... + ( - 1) + 2011
=(-1) . 1005 + 2011
= ( - 1005) + 2011
= 1006
1-2+3-4+...+2009-2010+2011
=(1-2)+(3-4)+(5-6)+...+(2009-2010)+2011 có 1005 cặp
=(-1)+(-1)+(-1)+...+(-1)+2011 có 1005 số (-1)
=(-1005)+2011
=1006
1. -x+20 = -(-15)-8+13
=> -x=15-8+13-20
=> -x=0
=> x=0
2. -(-10)+x=-13+(-9)+(-6)
=> 10+x=-13-9-6
=> x = -13-9-6-10
=> x = -38
3. 8-(-12)+10=-(-14)-x
=> 8+12+10=14-x
=> x = 14-8-12-10
=> x = -16
4. -(+12)+(-x)-(-3)=5-(-7)
=> -12-x+3=5+7
=> -x=5+7+12-3
=> -x=21
=> x=-21
5. 14-x+(-10)=-(-9)+(+15)
=> 14-x-10=9+15
=> -x=9+15-14+10
=> -x=20
=> x=-20
6. 12-(-17)+(-3)=-5+x
=> 12+17-3+5=x
=> x=31
7. x-(-19)-(+32)=14-(+16)
=> x+19-32=14-16
=> x=14-16+32-19
=> x=11
8. x-|-15|-|7|=-(-9)+|-5|
=> x-15-7=9+5
=> x=9+5+7+15
=> x=36
9. 15-x+17=13-(-21)
=> 15-x+17=13+21
=> -x=13+21-15-17
=> -x=2
=> x=-2
10. -|-5|-(-x)+4=3-(-25)
=> -5+x+4=3+25
=> x=3+25-4+5
=> x=29
1/ Vì \(25⋮\left(2x-3\right)\)
nên \(2x-3\)là ước của 25
U(25)\(=\left\{1;-1;5;-5;25;-25\right\}\)
Suy ra \(2x-3=1\Rightarrow x=2\)
\(2x-3=-1\Rightarrow x=1\)
\(2x-3=5\Rightarrow x=4\)
\(2x-3=-5\Rightarrow x=-1\)
\(2x-3=25\Rightarrow x=14\)
\(2x-3=-25\Rightarrow x=-11\)
2: =>4x+1+12 chia hết cho 4x+1
=>\(4x+1\in\left\{1;-1;2;-2;3;-3;4;-4;6;-6;12;-12\right\}\)
hay \(x\in\left\{-\dfrac{1}{2};0;\dfrac{1}{4};-\dfrac{3}{4};\dfrac{1}{2};-1;\dfrac{3}{4};-\dfrac{5}{4};\dfrac{5}{4};-\dfrac{7}{4};\dfrac{11}{4};-\dfrac{13}{4}\right\}\)
3:\(x< =6\)
nên 3x<=18
=>3x-1<=17
=>\(3x-1\in\left\{2;4;6;8;10;12;14;16\right\}\)
=>\(3x\in\left\{3;5;7;9;11;13;15;17\right\}\)
hay \(x\in\left\{1;\dfrac{5}{3};\dfrac{7}{3};3;\dfrac{11}{3};\dfrac{13}{3};5;\dfrac{17}{3}\right\}\)