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\(x+\dfrac{1}{2}+\dfrac{3}{8}=\dfrac{17}{16}\\ x+\dfrac{7}{8}=\dfrac{17}{16}\\ x=\dfrac{17}{16}-\dfrac{7}{8}\\ x=\dfrac{3}{16}\)
\(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+...+\dfrac{1}{x}=\dfrac{127}{256}\)
Đặt VT là A
\(\Rightarrow2A=1+\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{2}{x}\)
\(2A-A=\left(1+\dfrac{1}{2}+\dfrac{1}{4}+...+\dfrac{2}{x}\right)-\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+...+\dfrac{1}{x}\right)=\dfrac{127}{256}\)
\(\Leftrightarrow A=1-\dfrac{1}{x}=\dfrac{127}{256}\)
\(\Leftrightarrow\dfrac{1}{x}=\dfrac{129}{256}\)
\(\Rightarrow x=\dfrac{256}{129}\)
a, 8 x 6/32 x 1/5 = 3/10
8 x 6/32 x 1/5 = 8 x 3/16 x 1/5 = 3/10
b, 15/16 x 36/35 x 28 = 27
1/2+1/4+1/8+1/16+1/32+1/64
Ta thấy:
1/2=1/1-1/2
1/4=1/2-1/4
1/8=1/4-1/8....
1/64=1/32-1/64
A= 1/1-1/2+1/2-1/4+1/4-1/8+.....+1/32-1/64
A=1 - 1/ 64
A= 63/64
\(\frac{32}{64}+\frac{16}{64}+\frac{8}{64}+\frac{4}{64}+\frac{2}{64}+\frac{1}{64}=\frac{63}{64}\)\(\frac{63}{64}\)
a, 2/8 + 5/6 = 1/4 +5/6 = 6/24 + 20/24 = 26/24
b,1/8 + 12/16 = 1/8 + 3/4 = 4/32 + 24/32 = 28/32
c, 1/4 + 6/30 = 1/4 + 1/5 = 5/20 + 4/20 = 9/29
d, 12/18 + 12/42 = 2/3 + 2/7 = 14/21 + 6/21 = 20/21
nhé
Bài 6 : rút gọn rồi tính
A ) 2/8 + 5/6 = 3/12 + 10/12 = 13/12.
B ) 1/8 + 12/16 = 1/8 + 6/8 = 7/8.
C ) 1/4 + 6/30 = 5/20+ 4/20 = 9/20.
D ) 12/18 + 12/42 = 14/21 + 6/21 = 20/21.
a: \(A=\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2+\left(\dfrac{1}{2}\right)^3+...+\left(\dfrac{1}{2}\right)^7\)
=>\(2\cdot A=1+\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2+...+\left(\dfrac{1}{2}\right)^6\)
=>\(2A-A=1-\left(\dfrac{1}{2}\right)^7=1-\dfrac{1}{128}=\dfrac{127}{128}\)
=>\(A=\dfrac{127}{128}\)
b: \(B=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{10\cdot11}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{10}-\dfrac{1}{11}\)
\(=1-\dfrac{1}{11}=\dfrac{10}{11}\)
rút gọn 16/8 = 2
1+ 16/8 = 1+ 2 = 3
đáp án là 3
bạn ơi có lẽ là sai rồi ạ mình nói là 1 + 16 phần 8 ạ