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a. \(0,1\left(2\right)=0+\frac{12-1}{90}=\frac{11}{90};0,1\left(3\right)=0+\frac{13-1}{90}=\frac{12}{90}=\frac{2}{15}\)
=> 0,1(2)+0,1(3)=11/90 + 2/15 = 11/90 + 12/90 = 23/90
b. \(0,7\left(3\right)=0+\frac{73-7}{90}=\frac{66}{90}=\frac{11}{15};0,3\left(7\right)=0+\frac{37-3}{90}=\frac{34}{90}=\frac{17}{45}\)
=> 0,7(3)+0,3(7)=11/15 + 17/45 = 33/45 + 17/45 = 50/45 = 10/9
a)\(0,1\left(2\right)+0,1\left(3\right)\)
=\(0,1+0,0\left(2\right)+0,1+0,0\left(3\right)\)
=\(0,2+0,0\left(1\right).2+0,0\left(1\right).3\)
=\(0,2+0,0\left(1\right).5\)
=\(0,2+\frac{1}{90}.5\)
=\(\frac{3,6}{18}+\frac{1}{18}\)
=\(\frac{4,6}{18}\)
\(2\times\left(x-\frac{1}{7}\right)=0\)
\(x-\frac{1}{7}=0:2=0\)
\(x=0+\frac{1}{7}\)
\(x=\frac{1}{7}\)
vậy \(x=\frac{1}{7}\)
\(\frac{x}{-4}=\frac{-3}{5}\)
\(\Leftrightarrow5x=-3.\left(-4\right)=12\)
\(x=\frac{12}{5}\)
vậy \(x=\frac{12}{5}\)
\(\frac{2,1}{0,7}=\frac{x}{3}\)
\(\Leftrightarrow2,1.3=0,7x\)
\(6,3=0,7x\)
\(x=6,3:0,7\)
\(x=9\)
vậy \(x=9\)
a) 2x(x - 1/7) = 0 b) x/-4 = -3/5 c) 2,1/0,7 = x/3
TH1: 2x = 0 => x = 0 x = -3/5 x 4 2,1 . 3 = 0,7 . x
TH2: x -1/7 = 0 => x = 0 + 1/7 => x = 1/7 x = -12/5 6,3 = 0,7 . x
x = 6,3 : 0, 7
x = 9
\(A=\dfrac{\dfrac{3}{11}+\dfrac{3}{3}-\dfrac{3}{7}}{\dfrac{9}{11}+\dfrac{9}{3}-\dfrac{9}{7}}-\dfrac{\dfrac{1}{3}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{8}}{\dfrac{7}{6}+\dfrac{7}{8}-\dfrac{7}{10}+\dfrac{7}{16}}\)
\(=\dfrac{1}{3}-1:\dfrac{7}{2}=\dfrac{1}{3}-\dfrac{2}{7}=\dfrac{1}{21}\)
0,7(3)+0,3(7)
=73/99+37/99=110/99=1,(1)