Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Tính phải k nhỉ?
`1)`
`2x + 3x + 5x`
`= (2 + 3 + 5)x`
`= 10x`
`2)`
`2.x - x + 3.x`
`= (2 - 1 + 3)x`
`= 4x`
`3)`
`9.x - 3 - 3.x`
`= (9 - 3)x - 3`
`= 6x - 3`
`4)`
Thiếu dấu, bạn bổ sung thêm
`5)`
`x - 0,2x - 0,1x`
`= (1 - 0,2 - 0,1)x`
`=0,7x`
`6)`
\(\dfrac{7}{2}x-\dfrac{1}{2}x=\left(\dfrac{7}{2}-\dfrac{1}{2}\right)x=3x\)
TH1 : x < -1/30
=> 3/4 - 0,2 x = 3x + 0,1
=> 0,85 = 3,2 x
=> x = 64/17 > -1/30 ( loại )
TH2 : 15/4 > x > -1/30
=> 3/4 - 0,2 x = -3x + 1
=> -1/4 = -3,2x
=> x = 12,8 > 15/4 ( loại )
TH3 : x > 15/4
=> 0,2x - 3/4 = -3x + 0,1
=> - 3,2x = -0,85
=> x = 17/64 < 15/4 ( loại )
Vậy x thuộc rỗng
b) \(\dfrac{4}{5}-\dfrac{3}{4}:x=0,3\)
\(\Rightarrow0,8-0,75:x=0,3\)
\(\Rightarrow0,75:x=0,5\)
\(\Rightarrow x=1,5\)
c) \(\dfrac{-3}{2}-\dfrac{1}{4}x=1\dfrac{1}{3}-0,2x\)
\(\Rightarrow\dfrac{-3}{2}-\dfrac{4}{3}=\dfrac{1}{4}x-\dfrac{1}{5}x\)
\(\Rightarrow x=\dfrac{-17}{6}\cdot20\)
\(\Rightarrow x=\dfrac{-170}{3}\)
0,2x = 3*2 +1/3
0,2x = 7/3
x = 7/3 : 0,2
x = 7/3 * 10/2
x = 35/3
\(\Rightarrow\)0,2x=7/3
\(\Rightarrow\)1/5x=7/3
\(\Rightarrow\)x = 7/3:1/5
\(\Rightarrow\)x = 35/3
\(\dfrac{1}{2}x+0,2x-x-\dfrac{1}{5}=2\dfrac{3}{5}\\ \dfrac{1}{2}x+0,2x-x-\dfrac{1}{5}=\dfrac{13}{5}\\ x\cdot\left(\dfrac{1}{2}+0,2-1\right)=\dfrac{14}{5}\\ x\cdot\left(\dfrac{5}{10}+\dfrac{2}{10}+\dfrac{10}{10}\right)=\dfrac{14}{5}\\ x\cdot\dfrac{17}{10}=\dfrac{14}{5}\\ x=\dfrac{14}{5}:\dfrac{17}{10}\\ x=\dfrac{14}{5}\cdot\dfrac{10}{17}\\ x=\dfrac{28}{17}\)
\(\dfrac{1}{5}x-\dfrac{2}{3}x-\dfrac{2}{3}-\dfrac{1}{3}=0\)
\(\Leftrightarrow\dfrac{-7}{15}x-1=0\)
\(\Leftrightarrow\dfrac{-7x}{15}=1\)
\(\Leftrightarrow x=\dfrac{-15}{7}\)
0,2x - \(\dfrac{2}{3}x\)- \(\dfrac{2}{3}\)=\(\dfrac{1}{3}\)
<=> \(\dfrac{-1,4}{3}\)x=1
<=> x = \(\dfrac{-3}{1,4}\)
|-1,3.x+1/2| = |-5/6+0,2.x|
TH1: -1,3.x+1/2 = -5/6+0,2.x
=> -1,3.x - 0,2.x = -5/6 - 1/2
-1,5.x = -4/3
x = -8/9
TH2: -1,3.x+1/2 = 5/6-0,2.x
=> -1,3.x + 0,2.x = 5/6-1/2
-1,1.x = 1/3
x = -10/33
KL:...
\(\left|0,2x-\frac{3}{4}\right|=\left|-3x+0,1\right|\)
\(\Rightarrow0,2x-\frac{3}{4}=\hept{\begin{cases}-3x+0,1\\-\left(-3x+0,1\right)=3x-0,1\end{cases}}\)
\(\Rightarrow0,2x=\hept{\begin{cases}-3x+\frac{17}{20}\\3x+\frac{13}{20}\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}3,2x=\frac{17}{20}\\-2,8x=\frac{13}{20}\end{cases}}\)