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\(0,25^4.1024=?\)
Đổi \(0,25=\frac{25}{100}=\frac{1}{4}\)
Ta có : \(\frac{1^4}{4}=\frac{\left(1\right)^4}{4^4}=\frac{1.1.1.1}{4.4.4.4}=\frac{1}{256}\)
Mà \(\frac{1}{256}.1024=\frac{1}{256}.\frac{1024}{1}=\frac{1024}{256}=4\)
Vậy \(0,25^4.1024=4\)
(0,25)^4.1024
=(1/4)^4.1024
=1⁴/4⁴.1024
=1/256.1024
=4
=>(0,25)^4.1024=4
Hok tốt
(0,25)4 x 1024
\(=\left(\frac{1}{4}\right)^4\times1024\)
\(=\frac{1^4}{4^4}\times2^{10}\)
\(=\frac{1}{\left(2^2\right)^4}\times2^{10}\)
\(=\frac{1}{2^8}\times2^{10}=2^2=4\)
Câu a tự làm nhé
b, \(\frac{2x+3}{24}=\frac{3x-1}{32}\)
\(\Leftrightarrow32(2x+3)=24(3x-1)\)
\(\Leftrightarrow64x+96=72x-24\)
\(\Leftrightarrow64x+96-72x=-24\)
\(\Leftrightarrow96-8x=-24\Leftrightarrow x=15\)
\(x:\left(0,25\right)^4=\left(0,5\right)^2\)
\(x:\left(\frac{1}{4}\right)^4=\left(\frac{1}{2}\right)^2\)
\(x:\left[\left(\frac{1}{2}\right)^2\right]^4=\left(\frac{1}{2}\right)^2\)
\(x:\left(\frac{1}{2}\right)^8=\left(\frac{1}{2}\right)^2\)
\(x=\left(\frac{1}{2}\right)^2\cdot\left(\frac{1}{2}\right)^8=\left(\frac{1}{2}\right)^{10}=\frac{1}{1024}\)
\(=\dfrac{5}{2}\cdot\dfrac{1}{2}+\dfrac{3}{2}=\dfrac{5}{4}+\dfrac{6}{4}=\dfrac{11}{4}\)
\(\dfrac{5}{2}\times\sqrt{0,25}+\left|\dfrac{-9}{4}\right|\)
\(=\dfrac{5}{2}\times\dfrac{1}{2}+\dfrac{9}{4}\)
\(=\dfrac{5}{4}+\dfrac{9}{4}\)
\(=\dfrac{7}{2}\)
\(\left(0,25\right)^4\cdot1024\)
\(=\frac{1}{256}.1024\)
\(=4\)
\(\left(0,25\right)^4.1024=\left(\frac{1}{4}\right)^4.1024=\frac{1^4}{4^4}.1024=\frac{1}{16}.1024=\frac{1024}{16}=58\)
(0,25)4x1024
=1024x0,25x0,25x0,25x0,25
=1024:4:4:4:4
=1024:(4x4x4x4)
=1024:256
=4
TÌM X:
a) 2x - 3 = \(\frac{1}{2}\)
2x = \(\frac{1}{2}+3\)
2x = \(\frac{7}{2}\)
x = 2 : \(\frac{7}{2}\)
x = 2 . \(\frac{2}{7}\)
x = \(\frac{4}{7}\)
b) /x+1/ = 0.25
/x+1/ = \(\frac{1}{4}\)
\(\orbr{\begin{cases}x+1=\frac{1}{4}\\x+1=-\frac{1}{4}\end{cases}}\)
\(\orbr{\begin{cases}x=\frac{1}{4}-1\\x=-\frac{1}{4}-1\end{cases}}\)
\(\orbr{\begin{cases}x=-\frac{3}{4}\\x=-\frac{5}{4}\end{cases}}\)
c) 32 : 2x = 2
\(2x=32:2\)
\(2x=16\)
\(x=16:2\)
\(x=8\)
~GOOD STUDY~