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a) \(x:0,1+x:0,2=5,1\)
\(\Leftrightarrow x:\left(0,1+0,2\right)=5,1\)
\(\Leftrightarrow x:0,3=5,1\)
\(\Leftrightarrow x=5,1.0,3\)
\(\Leftrightarrow x=1,53\)
b) \(5:x-2,6:x=2,5\)
\(\Leftrightarrow\left(5-2,6\right):x=2,5\)
\(\Leftrightarrow2,4:x=2,5\)
\(\Leftrightarrow x=2,4:2,5\)
\(\Leftrightarrow x=0,96\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) TH1: \(x< 2,5\) , ta có:
\(2,5-x=1,3\)
\(x=2,5-1,3=1,2\)
TH2: \(x\ge2,5\), ta có:
\(x-2,5=1,3\)
\(x=1,3+2,5=3,8\)
Vậy \(\orbr{\begin{cases}x=1,2\\x=3,8\end{cases}}\)
b) \(1,6-\left|x-0,2\right|=0\)
\(\Rightarrow\left|x-0,2\right|=1,6\)
TH1: \(x< 0,2\) ta có:
\(0,2-x=1,6\Rightarrow x=0,2-1,6=-1,4\)
TH2: \(x\ge0,2\) ta có:
\(x-0,2=1,6\Rightarrow x=1,6+0,2=1,8\)
Vậy \(\orbr{\begin{cases}x=-1,4\\x=1,8\end{cases}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
=> 3/4.x - 1/2.x = 2,5
=> 1/4.x = 2,5
=> x = 2,5 : 1/4
=> x = 2,5 . 4
=> x = 10
dấu .=x ( nhân )
3/4x-1/2x=5/2
x.(3/4-1/2)=5/2
x.1/4=5/2
x=5/2:1/4
x=5/2.4/1
x=10/1
đúng thì tích nha
![](https://rs.olm.vn/images/avt/0.png?1311)
tìm x , biết :
a . 1,5 . x + 2,5 = 1
\(1,5.x=-1,5\)
\(x=\dfrac{-1,5}{1,5}\)
\(x=-1\)
b . ( 0,5 . x - 1,3 ) : 0,5 = -1,7
\(0,5.x-1,3=-0,85\)
\(0,5x=-2,15\)
\(x=\dfrac{-2,15}{0,5}\)
\(x=-4,3\)
c . 1,75 .x - 1,5 . x = 0,84
\(x\left(1,75-1,5\right)=0,84\)
\(x.0,25=0,84\)
\(x=3,36\)
d . x + 75% . x + 125% = 1
\(x+\dfrac{75}{100}.x+\dfrac{125}{100}=1\)
\(x+\dfrac{3}{4}.x+\dfrac{5}{4}=1\)
\(x+\dfrac{3}{4}.x=-\dfrac{1}{4}\)
\(x.\left(1+\dfrac{3}{4}\right)=-\dfrac{1}{4}\)
\(x.1,75=-\dfrac{1}{4}\)
\(x=-\dfrac{1}{7}\)
e . x - 25% .x + 75% = 1
\(x-\dfrac{25}{100}.x+\dfrac{75}{100}=1\)
\(x-\dfrac{1}{4}.x+\dfrac{3}{4}=1\)
\(x-\dfrac{1}{4}.x=\dfrac{1}{4}\)
\(x.\left(1-\dfrac{1}{4}\right)=\dfrac{1}{4}\)
\(x.\dfrac{3}{4}=\dfrac{1}{4}\)
\(x=\dfrac{1}{3}\)
f . | x - 1,5 | = 2,37
TH1 : \(x-1,5=2,37\)
\(x=2,37+1,5\)
\(x=3,87\)
TH2 : \(x-1,5=-2,37\)
\(x=-2,37+1,5\)
\(x=-0,87\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)25,52 - x : 2,5 = 4,61
x : 2,5 = 25,52 - 4,61
x ; 2,5 = 20,91
x = 20,91 x 2,5
x = 52,275
b) 12,6 - x + 4,5 = 4,61
12,6 - x = 4,61 - 4,5
12,6 - x = 0,11
x = 12,6 - 0,11
x = 12,49
c) x - 75/100 = 125/100 + 9/10
x - 0,75 = 1,25 + 0,9
x - 0,75 = 2,15
x = 2,15 + 0,75
x = 2,90
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left|3,5-x\right|=1,3\)
\(\Rightarrow\left[{}\begin{matrix}3,5-x=1,3\\3,5-x=-1,3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=3,5-1,3\\x=3,5+1,3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2,2\\x=4,8\end{matrix}\right.\)
b) \(1,6-\left|x-0,2\right|=0,4\)
\(\Rightarrow\left|x-0,2\right|=1,2\)
\(\Rightarrow\left[{}\begin{matrix}x-0,2=1,2\\x-0,2=-1,2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=1,2+0,2\\x=-1,2+0,2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=1,4\\x=-1\end{matrix}\right.\)
\(\left|3,5-x\right|=1,3\)
\(\Rightarrow\left[{}\begin{matrix}3,5-x=1,3\Rightarrow x=2,2\\3,5-x=-1,3\Rightarrow x=4,8\end{matrix}\right.\)
\(1,6-\left|x-0,2\right|=0,4\)
\(\Rightarrow\left|x-0,2\right|=1,2\)
\(\Rightarrow\left[{}\begin{matrix}x-0,2=1,2\Rightarrow x=1,4\\x-0,2=-1,2\Rightarrow x=-1\end{matrix}\right.\)
\(\left|x-1,5\right|+\left|2,5-x\right|=0\)
\(\left\{{}\begin{matrix}\left|x-1,5\right|\ge0\\\left|2,5-x\right|\ge0\end{matrix}\right.\)
\(\Rightarrow\left|x-1,5\right|+\left|2,5-x\right|\ge0\)
Dấu "=" xảy ra khi:
\(\left\{{}\begin{matrix}\left|x-1,5\right|=0\Rightarrow x=1,5\\\left|2,5-x\right|=0\Rightarrow x=2,5\end{matrix}\right.\)
\(1,5\ne2,5\Rightarrow x\in\varnothing\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 1 giờ 15 phút +75 phút +1,25 giờ x8
=(1 giờ 15 phút +75 phút)+ 10 giờ
=1 giờ 90 phút +10 giờ
=2gio 30 phút+10 giờ
=12 giờ 30 phút
b.2 phút 30 giây x 14 +15 phút -2,5 phút x4
=28 phút 420 giây +(15 phút -2,5 phút x4)
=35 phút + (15 phút -10 phút)
=35 phút +5 phút
=40 phút
![](https://rs.olm.vn/images/avt/0.png?1311)
0,04 . x - 0,05 . x = 11
=> ( 0,04 - 0,05 ) . x = 11
=> -0,01 . x = 11
=> x = 11 : (-0,01)
=> x = -1100
0.04.x-0.05.x=11
x(0.04-0.05)=11
x.(-0.01)=11
x=11.(-0.01)
x=-0.11
0,2 . x - 75 : 2,5 = 6,08 : 0,04
<=> 0,2x - 30 = 152
<=> 0,2x = 182
<=> x = 910
0,2 x x - 75 : 2,5 = 6,08 : 0,04
0,2 x x - 50 = 152
0,2 x x = 152 + 50
0,2 x x = 202
x = 202 : 0,2
x = 1010