(x+4) +(x+7) + .........+ (x+ 28 ) = 156
(x+2) + (x+4) + ( x +6 ) +........+ (x+ 1996 ) = 998000
11x (x-6 ) = 4 x x +11
x+2 x x + 3 x x +......+ 10 x x =165
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1/ Suy ra: -35 + 7x - 2x + 20 = 15
5x - 15 = 15
5x = 30
x = 6
2/ Suy ra: 4x - 20 - 3x - 21 = -19
x - 41 = -19
x = 22
3/ Suy ra: 8 - 4x + 3x - 15 = 14
-7 -x = 14
x = -7 -14
x = -21
4/ Suy ra: 7x - 63 - 30 + 5x = -6 + 11x
7x + 5x - 11x = -6 +63 + 30
x = 87
5/ Suy ra: -21x +35 + 14x - 28 = 28
-21x + 14x = 28 +28 - 35
-7x = 21
x= -3
6/ Suy ra: 20 - 5x + 7x - 14 = -2
2x = -8
x = -4
7/ Suy ra: 4x +15 -5x = 7
-x = -8
x = 8
8/ Suy ra: 5x - 35 +30 -10x = 20
-5x - 5 = 20
-5x = 25
x = -5
9/ Suy ra: 35 - 7x + 5x - 10 = 15
-7x + 5x = 15 +10 - 35
-2x = -10
x = 5
nhiều quá :((
\(a,2\left(x-5\right)-3\left(x+7\right)=14\)
\(2x-10-3x-21=14\)
\(-x-31=14\)
\(-x=45\)
\(x=45\)
\(b,5\left(x-6\right)-2\left(x+3\right)=12\)
\(5x-30-2x-6=12\)
\(3x-36==12\)
\(3x=48\)
\(x=16\)
\(c,3\left(x-4\right)-\left(8-x\right)=12\)
\(3x-12-8+x=0\)
\(4x-20=0\)
\(4x=20\)
\(x=5\)
Cố nốt nha bn !
cảm ơn, bn nha:)))
mà hình như bạn TOP 3 trả lời câu hỏi pải ko nhỉ???
a) \(\left(\frac{3}{4}+x\right)\times\frac{7}{4}-5=\frac{7}{6}\)
\(\Leftrightarrow\left(\frac{3}{4}+x\right)\times\frac{7}{4}=\frac{37}{6}\)
\(\Leftrightarrow\frac{3}{4}+x=\frac{37}{6}:\frac{7}{4}=\frac{74}{21}\)
\(\Leftrightarrow x=\frac{74}{21}-\frac{3}{4}=\frac{233}{84}\)
Vậy ....
b) \(x\times12+13\times x+x:2+195=1995\)
\(\Leftrightarrow x\times12+x\times13+x\times0,5=1800\)
\(\Leftrightarrow x\times\left(12+13+0,5\right)=1800\)
\(\Leftrightarrow x\times25,5=1800\)
\(\Leftrightarrow x=\frac{1200}{17}\)
c) (x+1)+(x+4)+(x+7)+....+(x+28) = 156
<=> (x+x+x+...+x)+(1+4+7+...+28) = 156
<=> 10x + 145 = 156
<=> 10x = 11
<=> x = 1,1
Vậy ...
(X -10/1994 -1) + (X-8/1996 - 1) + (X-6/1998 - 1)+ (X-4/2000 - 1) + (X-2/2002 - 1) = (X-2002/2 - 1) + (X-2000/4 - 1) + (X-1998/6 - 1) + (X-1996/8 - 1) + (X-1994/10 - 1)
=> x-2004/1994 + x-2004/1996 + x-2004/1998 + x-2004/2000 + x-2004/2002 = x-2004/2 + x-2004/4 + x-2004/6 + x-2004/8 + x-2004/1994
=> x-2004/1994 + x-2004/1996 + x-2004/1998 + x-2004/2000 + x-2004/2002 - x-2004/2 - x-2004/4 - x-2004/6 - x-2004/8 - x-2004/1994 = 0
=> (x - 2004)(1/994 + 1/1996 + 1/1998 + 1/2000 + 1/2002 + 1/2 + 1/4 + 1/6 + 1/8) = 0
Mà (1/994 + 1/1996 + 1/1998 + 1/2000 + 1/2002 + 1/2 + 1/4 + 1/6 + 1/8) \(\ne\)0
=> x - 2004 = 0
=> x = 2004
Vậy x = 2004
1.
$-7(5-x)-2(x-10)=15$
$-35+7x-2x+20=15$
$5x-15=15$
$5x=30$
$x=30:5=6$
2.
$3(x-4)-(8-x)=12$
$3x-12-8+x=12$
$4x-20=12$
$4x=12+20=32$
$x=32:4=8$