tính:
\(A=\frac{\left(\frac{3}{4}\right)^3+\left(\frac{5}{4}\right)^3-5.\left(\frac{3}{4}-\frac{5}{4}\right)}{\left(-\frac{5}{8}\right)^2+\left(\frac{2}{3}\right)^2-\frac{5}{6}}\)
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a)
\(\begin{array}{l}\frac{1}{9} - 0,3.\frac{5}{9} + \frac{1}{3}\\ = \frac{1}{9} - \frac{3}{{10}}.\frac{5}{9} + \frac{1}{3}\\ = \frac{1}{9} - \frac{3}{{2.5}}.\frac{5}{{3.3}} + \frac{1}{3}\\ = \frac{1}{9} - \frac{1}{6} + \frac{1}{3}\\ = \frac{2}{{18}} - \frac{3}{{18}} + \frac{6}{{18}}\\ = \frac{5}{{18}}\end{array}\)
b)
\(\begin{array}{l}{\left( {\frac{{ - 2}}{3}} \right)^2} + \frac{1}{6} - {\left( { - 0,5} \right)^3}\\ = \frac{4}{9} + \frac{1}{6} - \left( {\frac{{ - 1}}{2}} \right)^3\\ = \frac{4}{9} + \frac{1}{6} - \left( {\frac{{ - 1}}{8}} \right)\\ = \frac{4}{9} + \frac{1}{6} + \frac{1}{8}\\ = \frac{{32}}{{72}} + \frac{{12}}{{72}} + \frac{9}{{72}}\\ = \frac{{53}}{{72}}\end{array}\)
\(=\dfrac{35.85\cdot14}{0.5+2.3}\cdot\dfrac{6}{17}\cdot\dfrac{16.8}{259,2}-\left(4.625-\dfrac{13}{6}:\dfrac{26}{3}\right):\left(3.25:2.25\right)\)
\(=\dfrac{1673}{408}-\dfrac{315}{104}=\dfrac{1421}{1326}\)
=> A = \(\frac{\frac{3}{64}+\frac{5}{64}-\frac{5}{2}}{\frac{-5}{64}+\frac{2}{9}-\frac{5}{6}}\)= \(\frac{\frac{1}{8}-\frac{5}{2}}{\frac{83}{576}-\frac{5}{6}}\)= \(\frac{\frac{-19}{8}}{\frac{-397}{576}}\)= \(\frac{1368}{397}\)
A = \(\frac{171}{134}\)