Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(x^2-y^2+z^2-t^2-2xz+2yt\)
\(=\left(x^2-2xz+z^2\right)-\left(y^2+2yt-t^2\right)\)
\(=\left(x-z\right)^2-\left(y-t\right)^2\)
\(=\left(x-z+y-t\right).\left(x-z-y+t\right)\)
chắc chắn 100% là đúng nha bạn
\(x^2-y^2+z^2-t^2-2xz+2yt\)
\(=\left(x^2+z^2-2xz\right)-\left(y^2+t^2-2yt\right)\)
\(=\left(x-z\right)^2-\left(y-t\right)^2\)
\(=\left(x-z-y+t\right)\left(x-z+y-t\right)\)
x2-y2+z2-t2-2xz+2yt
=(x2-2xz+z2)+(-y2+2yt-t2)
=(x2-2xz+z2)-(y2-2yt+t2)
=(x-z)2-(y-t)2
=(x-z-y+t)(x-z+y-t)
a, \(\left(x+1\right)^2-25=\left(x+1-5\right)\left(x+1+5\right)=\left(x-4\right)\left(x+6\right)\)
b, \(\left(xy+4\right)^2-4\left(x+y\right)^2=\left(xy+4\right)^2-\left(2x+2y\right)^2=\left(xy+4-2x-2y\right)\left(xy+4+2x+2y\right)\)
c, xem lại đề nhé
2xy + x2 + y2 = ( x + y )2 = ( x+y ) ( x + y )
( 25z -15n )2 = ( 25z - 15n ) ( 25z -15n )
\(a,x^6-y^6=\left(x^3\right)^2-\left(y^3\right)^2=\left(x^3-y^3\right)\left(x^3+y^3\right).\)
\(=\left(x-y\right)\left(x^2+xy+y^2\right).\left(x+y\right)\left(x^2-xy+y^2\right)\)
\(b,9x^2+y^2+6xy=\left(3x\right)^2+2.3x.y+y^2=\left(3x+y\right)^2\)
\(c,6x-9-x^2=-\left(x^2-6x+9\right)=-\left(x^2-2.x.3+3^2\right)=-\left(x-3\right)^2\)
a)x3+3x2+3x+1
=x3+3x2*1+3x*12+13
=(x+1)3
b)(x+y)2-9x2
=y2+2xy+x2-9x2
=y2-2xy+4xy-8x2
=y(y-2x)+4x(y-2x)
=(y-2x)(y+4x)
\(\left(x^2-2xz+z^2\right)-\left(y^2-2yt+t^2\right)=\left(x-z\right)^2-\left(y-t\right)^2=\left(x-z+y-1\right)\left(x-z-y+t\right)\)
Chúc Bạn học tốt
T I C K nha
Cau nay ko co dap an sao